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lecture05 - Exam I Free Fall and Apparent Weight Today's...

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Physics 101: Lecture 5, Pg 1 Free Fall and Apparent Weight Physics 101: Lecture 05 Today’s lecture will cover Textbook Sections 4.3,4.5 Check iclicker scores! Exam 1 is Feb 27. Exam I
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Physics 101: Lecture 5, Pg 2 Review from Lecture 4 Constant Acceleration Equations of Motion x = x 0 + v 0 t + 1/2 at 2 v = v 0 + at v 2 = v 0 2 + 2a(x-x 0 ) S F = m a Draw Free Body Diagram Write down equations (which variables do you know, which don’t you know?) Solve Today: look at Gravity as force
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Physics 101: Lecture 5, Pg 3 Free Fall Only force acting on object is GRAVITY Newton’s 2 nd Law S F y = ma y Force is Weight = mg (near surface of earth) » S F y = ma y » -mg = ma y » a y = -g (- sign tells us it is in y direction or down). Acceleration is ALWAYS g downwards Position may be positive, zero or negative Velocity may be positive, zero or negative Acceleration is always g downwards y x y = y 0 + v y0 t - 1/2 gt 2 v y = v y0 - gt v y 2 = v y0 2 - 2g(y-y 0 )
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