lecture03 - Physics 101: Lecture 03 Kinematics Today's...

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Physics 101: Lecture 3, Pg 1 Kinematics Physics 101: Lecture 03 Today’s lecture will cover Textbook Sections 3.1-3.3 (and some Ch. 4)
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Physics 101: Lecture 3, Pg 2 Announcements HW 1 and HW2 are due Tuesday January 31 at 6 am. Office hours starts on January 30, Monday in 32 Loomis Read the course description & FAQ on the course web site! E-mail policy reminder: subject line should be Physics 101
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Physics 101: Lecture 3, Pg 3 Homework 2 Example Calculate the tension in the left string. x-direction: S F=ma -T L +T R cos( q )= 0 T L = T R cos( q ) y-direction: S F=ma T R sin( q ) – Mg = 0 T R = Mg / sin( q ) Combine: T L = Mg cos( q )/sin( q ) T L W q T R y x
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Physics 101: Lecture 3, Pg 4 Overview Kinematics: Description of Motion Position and displacement velocity »average »instantaneous Acceleration »instantaneous Relative velocity (first pass)
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Physics 101: Lecture 3, Pg 5 Position vs Time Plots Gives location at any time. Displacement is change in position. Slope gives instantaneous velocity. x (m) t 4 3 -3 Position at t=3, x(3) = Displacement between t=5 and t=1. D x = Average velocity between t=5 and t=1 . v = 1 -1.0 m -0.25 m/s 1.0 m - 2.0 m = -1.0 m -1 m / 4 s = -0.25 m/s
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Physics 101: Lecture 3, Pg 6 6 Velocity vs Time Plots Gives velocity at any time. Area gives displacement Slope gives instantaneous acceleration. v (m/s) t 4 3 -3 velocity at t=2, v(2) = Change in v between t=5 and t=3. D v = Average acceleration between t=5 and t=3: a = Displacement between t=0 and t=3: D x= Average velocity between t=0 and t=3? v= 3 m/s 7.5 m t=0 to t=1: ½ (3m/s) (1 s) = 1.5 m 7.5 m / 3s = 2.5 m/s -2 m/s – 3 m/s = -5 m/s -5 m/s / (2 s) = -2.5 m/s 2 t=1 to t=3: (3m/s) (2 s) = 6 m
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This note was uploaded on 02/05/2012 for the course PHYS 101 taught by Professor Ha during the Spring '11 term at University of Illinois at Urbana–Champaign.

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lecture03 - Physics 101: Lecture 03 Kinematics Today's...

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