102 lect19_handout - Physics 102: Lecture 19 Lenses and...

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Physics 102: Lecture 19, Slide 1 Physics 102: Lecture 19 Lenses and your EYE Ciliary Muscles
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Physics 102: Lecture 19, Slide 2 3 Cases for Converging Lenses Image Object Upright Enlarged Virtual Inside F Image Object Inverted Enlarged Real Between F & 2F Object Image Inverted Reduced Real Past 2F
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Physics 102: Lecture 19, Slide 3 Only 1 Case for Diverging Lenses F F Object P.A. Image is always virtual, upright, and reduced . Image
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Physics 102: Lecture 19, Slide 4 Preflight 19.1 A converging lens is used to project a real image onto a screen. A piece of black tape is then placed over the upper half of the lens.
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Physics 102: Lecture 19, Slide 5 Lens Equation Same as mirror equation cm 10 1 1 cm 15 1 = + i d cm 30 = i d o i d d m = 2 = F F Object P.A. d o d i f Image 1 d o + 1 d i = 1 f •d o = distance object is from lens: Positive: object in front of lens • Negative: object behind lens i = distance image is from lens: • Positive: real image (behind lens) • Negative: virtual image (in front of lens) f = focal length lens: • Positive: converging lens • Negative: diverging lens
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Physics 102: Lecture 19, Slide 6 Multiple Lenses Image from lens 1 becomes object for lens 2 1 f 1 f 2 2 Lens 1 creates a real, inverted and enlarged image of the object. Lens 2 creates a real, inverted and reduced image of the image from lens 1. The combination gives a real, upright, enlarged image of the object.
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Physics 102: Lecture 19, Slide 7 f 1 f 2 First find image from lens 1. cm 10 1 1 cm 15 1 = + i d cm 30 = i d d o = 15 cm f 1 = 10 cm d i = 30 cm f 2 = 5 cm 1 2 Multiple Lenses: Image 1
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Physics 102: Lecture 19, Slide 8 f 1 f 2 Now find image from lens 2.
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This note was uploaded on 02/05/2012 for the course PHYS 102 taught by Professor Carruba during the Spring '09 term at University of Illinois at Urbana–Champaign.

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102 lect19_handout - Physics 102: Lecture 19 Lenses and...

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