Unformatted text preview: o dP= p’-p = 0 = no evolution • AA=p^2 Aa=2pq aa=q^2 • Nutrasweet o Di-peptide Phenylalamine (sp) + aspartic acid => PKU (Phenoketonurics can’t process phe) Phe (when in excess) => (by hydroxylase) tyrosine (in normal body) (Phe accumulates but can be broken down) In PKU body, phen => (by hydroxylase) tyrosine • However, Phen accumulates in body & is toxic Phenoketonurics damages phehydroxolate => accumulation PHe that can’t be broken down Those with recessive alleles don’t have enzyme to digest phe. (PKUs) • Dd= 2pq = 2(1-10^-2)10^-2 = 1/50 = .0198 • DD = p^2 == (1-10^-2) = .98 • Evolution (no agent p’=p and dP = 0) which is hardy weinberg o Selection o Migration o Mutation o Drift o other...
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This note was uploaded on 02/05/2012 for the course BIEB 150 taught by Professor Chao during the Winter '11 term at San Diego.
- Winter '11