3 - Gamete pool (p=f(A) q=f(a) => genotypes (AA/p Aa/2pq...

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Gamete pool (p=f(A) q=f(a)) => genotypes (AA/p² Aa/2pq aa/q²) => gametepool (p’ q’)  If no evolution p’=p and Dp=p’-p=0 o frequency of p= p² + ½ pq / (total (p²+2pq+q²)) Selection: directional, stabilizing, and disruptive  Fitness = allele frequencies => get the percentages (p^2 2pq q^2 * 100) => get the number of individuals  that survived into adulthood => get p’ Fitness= ratio of survival over gene frequency  o # of individuals/ p^2 or 2pq or q^2 = 1-S o 1- S (selection coefficient)  S= 0 = no evolution because there’s no selection S=1 = everything has died AA Aa aa HW 2pq Q^2 Fit 1 1 1-S After selection= p^2   2pq q^2 * (1-S) o TOTAL = 1-q^2*S P’= p^2+ 2pq/2 / 1-q^2S =  p/(1-q^2S) DP= pq^2S / 1-q^2S Dp will always be positive because it’s always trying to remove q (directional in p)
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This note was uploaded on 02/05/2012 for the course BIEB 150 taught by Professor Chao during the Winter '11 term at San Diego.

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