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3 - Gamete pool(p=f(A q=f(a => genotypes(AA/p Aa/2pq aa/q...

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Gamete pool (p=f(A) q=f(a)) => genotypes (AA/p ²  Aa/2pq aa/q ² ) => gametepool (p’ q’)  If no evolution p’=p and Dp=p’-p=0 o frequency of p= p ²  +  ½  pq / (total (p ² +2pq+q ² )) Selection: directional, stabilizing, and disruptive  Fitness = allele frequencies => get the percentages (p^2 2pq q^2 * 100) => get the number of individuals  that survived into adulthood => get p’ Fitness= ratio of survival over gene frequency  o # of individuals/ p^2 or 2pq or q^2 = 1-S o 1- S (selection coefficient)  S= 0 = no evolution because there’s no selection S=1 = everything has died AA Aa aa HW p ² 2pq Q^2 Fit 1 1 1-S After selection= p^2   2pq q^2 * (1-S) o TOTAL = 1-q^2*S P’= p^2+ 2pq/2 / 1-q^2S =  p/(1-q^2S) DP= pq^2S / 1-q^2S Dp will always be positive because it’s always trying to remove q (directional in p)
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