5 - Disruptive selection: AA=p=1 Aa=2pq=(1S) aa=q=1 P+q=1...

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Disruptive selection: AA=p²=1 Aa=2pq=(1-S) aa=q²=1 P+q=1     P’+q’=1     Delta P = p’-p (if in equilibrium delta p/q = 0) o P’ = p+dP     o So p+dp+dq+q=1 => 1+dp+dq=1 => dp+dq=0 so dp=-dq Delta q= q’-q o If one increases the other decreases P’= p²(1)+2pq ½ (1-s) / p²(1)+2pq(1-s)+q²(1)      o Total = 1-2pqS Q’= q²(1)+2pq ½ (1-s)/ total o Q²+pq-pqS/total o Q(q+p)-pqs/total o Q-pqs/total      Dq=q’-q o Q-pqs-q(1-2pqs)/1-2pqs o Q-pqs-q+2pq²s/1-2pqs o 2pq²s-pqs/1-2pqs o Pqs(2q-1)/1-2pqs     Q=1/2 then dq=0 and the graph of it will remain a constant straight horizontal line  If q is greater than one half then delta q will go up (diverge from 0, fixation) If q is less than one half then delta q will go down (diverge from 0, extinction) o
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This note was uploaded on 02/05/2012 for the course BIEB 150 taught by Professor Chao during the Winter '11 term at San Diego.

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