Lecture05_2012_Jan25

Lecture05_2012_Jan25 - Lecture 5 Purdue University Physics...

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Unformatted text preview: Lecture 5 Purdue University, Physics 220 1 Lecture 05 Forces and Motion beyond 1 D Textbook Sections 3.7, 4.1 PHYSICS 220 Lecture 5 Purdue University, Physics 220 2 • UNIMPORTABLE: • #00E9BF56,2.00,2.00 • #09B63F80,6.00,6.00 • #0E133429,2.00,2.00 • #225BEB92,4.00,4.00 • #80330CBF,6.00,6.00 • #803AF64C,6.00,6.00 • #809B0813,4.00,4.00 • #80E6096F,6.00,6.00 • #810C8D00,2.00,2.00 • #81709E6F,6.00,6.00 •#817EE11E,6.00,6.00 • #8279AE55,6.00,6.00 • #831033A0,4.00,4.00 • #8341E92B,4.00,4.00 • #834C955A,6.00,6.00 • #83CA7831,6.00,6.00 Lecture 5 Purdue University, Physics 220 3 Exercise Fred throws a ball 30 m/s vertically upward. How long does it take to hit the ground 2 meters below where he released it? y = y + v y0 t + 1/2 gt 2 v y = v y0 + gt v y 2 = v y0 2 + 2g(y-y ) y = y + v y0 t - 0.5 g t 2 y-y- v y0 t + 0.5g t 2 = 0-2 – 30 t + 0.5*9.8 t 2 = 0 ax 2 + bx + c = x =- b ± b 2- 4 ac 2 a t = 6.19 s or -.06 s x = 30 ± 30 2 + 4 2 2 9.8 9.8 Lecture 5 Purdue University, Physics 220 4 Exercise Fred throws a ball 30 m/s vertically upward. What is the maximum height the ball reaches? How long does it take to reach this height? v 2-v o 2 = 2 a ∆ y ∆ y = (v 2-v o 2 )/ (2 a) = -30 2 / (2 * (-9.8)) = 46 m v = v + a t t = (v-v ) / a = (0 – 30 m/s )/ (-9.8 m/s 2 ) = 3.1 seconds Lecture 4 Purdue University, Physics 220 5 Contact Force: Spring • Force exerted by a spring is directly proportional to the amount by which it is stretched or compressed....
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This note was uploaded on 02/05/2012 for the course PHYS 220 taught by Professor Chang during the Spring '09 term at Purdue.

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Lecture05_2012_Jan25 - Lecture 5 Purdue University Physics...

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