problem03_21

University Physics with Modern Physics with Mastering Physics (11th Edition)

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3.21: a) The time the quarter is in the air is the horizontal distance divided by the horizontal component of velocity. Using this time in Eq. (3.18), rounded. m 53 . 1 60 cos ) s m 4 . 6 ( 2 m) 1 . 2 )( s m 80 . 9 ( m) 1 . 2 ( 60 tan cos 2 tan 2 2 2 2 2 0 2 2 0 2 0 2 0 2 0 0 0 = ° - ° = - = - = - α v gx x v gx v x v y y x x y b) Using the same expression for the time in terms of the horizontal distance in
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Unformatted text preview: Eq. (3.17), . s m 89 . 60 cos ) s m 4 . 6 ( ) m 1 . 2 )( s m 80 . 9 ( 60 sin ) s m 4 . 6 ( cos sin 2-= - =-= v gx v v y...
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