This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: MGT 2250  Quiz #18
2 Sides A a Answers: my?“ s/< k s 1) A simple random sample of 40 items resulted in a sample mean of 32.
Assume a population standard deviation of 8.
a) Using a 95% conﬁdence level, how large a sample should be used to
provide a margin of error of 1.5? M “xx,Q L i _ ‘ a? p ‘ [gig for“ W’ém a
a, ? (orig?) ? we » ﬂ iii”;
if? J b) Using a 90% conﬁdence level, how large a sampie should be used to
provide a margin of error of 1.5? \
i ' ' r ,/ \
/( ﬁligiWQl'fﬂ i. E Mfg) {,E we \2
W , . \ a?" f "‘ ' W ‘7): ’g‘ in a i “ii"Mn. i S i x, i k g, g e c) Using a 99% conﬁdence level, how large a sample should he used to
provide a margin of error of1,5? w W k
f , v21
6 i
l I: m wwww E f k.» “’5’ " 57 in!“ kWh” «WV/M
re 3:” j x (1) Using a 95% conﬁdence level, how large a sample should be used to
provide a margin of error of 1.0? £2,” “a, R‘s l _ W W w \ rig W 
f/<;¢»§‘ } HE if} 2 if X 33 _& my [/Zf is
I} \E g i r“ or” t K e) Using a 95% conﬁdence level, how large a sample should be used to
provide a margin of error of 0.5 / [W fag} RX Wham 40?, < gifwéﬂjmgc j E} i, o a a? g
\«n / 2250Qui218P l 2) The minimum price per day to rent a car in t 6 United States has been
determined to be $40 and the maximum $95. %A sample of 50 rental prices
were determined to have a mean of $63.50. a) What is the planning value for the population standard deviation? 4/“ , , W W m
Egg: MW e 6 er W
e .r “.2” WWW ? MMWW ‘1 g :7? ? f“
i <75 of «
b) Using a 95% conﬁdence level, how large a sample should be used to
provide a margin of error of $5? c) Using a 95% conﬁdence level, how large a sample should be used to provide a margin of error of $1?
W; fi ’ ﬂ if”; W“; at
{i WQQ / if i <2 we «M f: WWW my ( g 1/ gig I 2/” a...” /
kw Now” My“ 3) A simple random sample of 1000 individuals provided 470 “Yes” responses,
:1) Using a 95% conﬁdence level, how large a sample slﬁLguld be used to We provide a margin of error of 0.03? w ' gw :39 (pea. g E '
m f r
/rrl?¢[email protected] @ ﬂaw
ml WW7T§ j i " ' :3 / 5% Jr?) W e! f \K {hwy K“ ‘g gkg’ﬁgﬁxiﬂ
b) Using a 95% conﬁdence level, how large a sample should be used to RNMMMWWWM provide a margin of error of 0.02? a "i ‘2’; , r if p mg: 1 weew
“Eider I ﬁb/ Le , i W WW. WWW MadmenTmawa‘ﬂ‘ c) Assuming you didn’t know the proportion “Yes” before collecting the
sample, what is the number would you need in your sample to ensure
a margin of error of 0.03 at a conﬁdence level of 95%? (ﬁﬂﬁaoadw/Miw “:4 “WWW .
e 5:? [i ’ \x 2250Qui218P 5 Km. ...
View
Full Document
 Summer '08
 Milne
 Standard Deviation, $1, 5%, $5, 2 w, 1 g

Click to edit the document details