q3key - Chem 171 Quiz 3 Version A (Key Chrom/Emp) 1 These

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Chem 171 Quiz 3 Version A (Key Chrom/Emp) 1 . These “fill-in-the-blanks” refer to the “Paper Chromatography” experiment. a. The degree to which species are separated is called resolution. b. Transition metal ions form complexes in solutions. 2 . A compound of Fe and O contains 1.83 g of Fe and 0.700 g O. What is the empirical formula of the oxide. Fe = 55.85. O =16.00. 1.83 g x 1 mol / 55.85 g = 0.0328 mol Fe 0.700 g x 1 mol / 16.00 g = 0.0438 mol O Fe: 0.0328 / 0.0328 = 1 and O: 0.0438 / 0.0328 = 1.34 Multiply by 3 Fe = 3 and O = 4 => Fe 3 O 4 Chem 171 Quiz 3 Version B 1. A chromatogram of Cr (III) cation was prepared. The height of the solvent front was 43.4 mm, while the center of Cr (III) spot was 8.8 mm below the solvent front. Calculate R f for Cr (III) ion. R f = Distance traveled by solute / Distance traveled by solvent front Dist traveled by solute = 43.4 mm – 8.8 mm = 34.6 mm R f = 34.6 mm / 43.4 mm = 0.797 2. Assuming 50 % yield, what mass of Zn will react with 25.00 mL of solution containing 2.074 g of CuCl
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q3key - Chem 171 Quiz 3 Version A (Key Chrom/Emp) 1 These

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