Math_112_Fall_2010.jkovalsky.Lesson_05_-_The_Cartesian_Coordinate_Plane

Math_112_Fall_2010.jkovalsky.Lesson_05_-_The_Cartesian_Coordinate_Plane

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Unformatted text preview: JORDAN KOVALSKY Math - 112 Spring 2010 WeBWorK Assignment Lesson 05 - The Cartesian Coordinate Plane Due Date: 09/17/2010 at 11:59pm CDT. The primary purpose of WeBWorK is to let you know that you are getting the correct answer or to alert you if you are making some kind of mistake. You can use the Feedback button on each problem page to send e-mail to the course instructors. 1. (1 pt) Calculate the distance between the points (-6, 1) and (6, 1). Distance = Calculate the distance between the points (6, -3) and (0, -3). Distance = 4. (1 pt) Find the midpoint of the line segment joining points P(15, 4) and Q(15, 6). Midpoint = ( , ) Find the midpoint of the line segment joining points P( 1 , 2 ) and 5 3 Q(0, 0). Midpoint = ( , ) Find the midpoint of the line segment joining points P(3, 3) and Q(5, 5). Midpoint = ( , ) Correct Answers: sqrt(144) sqrt(36) 2. (1 pt) Which point is farther from the origin, (3, -2) or (-4, 0.5)? ? Which point is farther from the origin, (-6, 7) or (9, 0)? ? Correct Answers: 15 5 1 / 10 2 / 6 4 4 * pi Correct Answers: Point 2 Point 1 5. (1 pt) The points P(6, -6) and Q(2, 4) are the endpoints of a diameter of a circle. Find the center of the circle. Center = ( , ) Find the radius of the circle. Radius = 3. (1 pt) The coordinates of points A, B, and C are A(5, 5), B(-2, 0), and C(-9, -5). Show that AB = BC by using the distance formula. AB = BC = Show that AB + BC = AC by using the distance formula. AC = What can you conclude from the previous parts? Correct Answers: 4 -1 sqrt(116) / 2 6. (1 pt) Correct Answers: sqrt(74) sqrt(74) sqrt(296) 1 The points P(-1, 3) and Q(-3, 1) are the endpoints of a diameter of a circle. Find the center of the circle. Center = ( , ) Find the radius of the circle. Radius = Equation: =0 Correct Answers: -2 2 sqrt(8) / 2 Correct Answers: x^2+y^2-6 9. (1 pt) 7. (1 pt) The point P(x, y) satisfies the condition that is equidistant from the points A(-2, -4) and B(3, 4). Find and simplify an equation relating x and y. By simplify, we mean that you should re-write your equation so there are no square roots or fractional exponents present. Equation: =0 The point P(x, y) satisfies the condition that it is half as far from (2, 1) as it is from (-3, -4). Find and simplify an equation relating x and y. By simplify, we mean that you should re-write your equation so there are no square roots or fractional exponents present. Equation: =0 Correct Answers: Z * ((y - 0) - -0.625 * (x - 0.5)) Correct Answers: c * (3 * x**2 + 3 * y**2 - 22 * x - 16 * y - 5) 8. (1 pt) The point P(x, y) satisfies the condition that its distance from the origin is 6 units. Find and simplify an equation relating x and y. By simplify, we mean that you should re-write your equation so there are no square roots or fractional exponents present. c Generated by the WeBWorK system WeBWorK Team, Department of Mathematics, University of Rochester The reflection of the point (-8, 6) over the x-axis is ( , ) The reflection of the point (3, 6) over the y-axis is ( , ) The reflection of the point (2, -7) over the origin is ( , ) Correct Answers: -8 -6 -3 6 -2 7 2 ...
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This note was uploaded on 02/07/2012 for the course MATH 112 taught by Professor Carlson during the Fall '08 term at Wisconsin.

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