Solution8

Solution8 - STAT 350 Homework #8 ch8:...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: STAT 350 Homework #8 ch8: 4,6,12,15,16,19,20,22,26,29 4. Let denote the population standard deviation of sheath thickness. The relevant hypotheses are: 05 . : 05 . : a H versus H This is because the company is interested in obtaining conclusive evidence that 05 . . A Type I error would be: concluding that the true standard deviation of sheath thickness is less than .05mm when, in fact, it is not. 6. Let denote the true average compressive strength of the mixture. The relevant hypotheses are: 300 , 1 : 300 , 1 : a H versus H A Type I error would be: concluding that the mixture meets the strength specifications when, in fact, it does not. A Type II error would be: concluding that the mixture does not meet the strength specifications when, in fact, it does. 12. (a) 87 . 2 50 06 . 1 34 43 . 34 z So, p-value = 2P(z > 2.87) = 2(.0021) = .0042 [Note: Since H a is a two-tailed test, the p-value is the sum of the area in the two tails. That is, p-value = P(z < -2.87) + P(z > 2.87) = 2P(z > 2.87)] (b) 87 . 2 50 06 . 1 34 57 . 33 z So, p-value = 2P(z < -2.87) = 2(.0021) = .0042 (c) 24 . 2 32 89 . 1 34 25 . 33 z So, p-value = 2P(z < -2.24) = 2(.0125) = .025 (d) 57 . 1 36 53 . 2 34 66 . 33 z So, p-value = 2P(z > 1.57) = 2(.0582) = .1164 15. Let denote the true average speedometer reading (at 55 mph). Since we are concerned about whether the speedometer readings may be too high or too low (compared to 55 mph), this requires a 2-sided test...
View Full Document

Page1 / 5

Solution8 - STAT 350 Homework #8 ch8:...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online