hw5-sol-sp11 - "#\$&"#\$&"#\$ \$ \$&&\$...

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Unformatted text preview: !"!#\$%&" #\$'&" !#\$# ( ,) ) * \$ ++ '- ( \$) '& .&\$ ++ 1. (10 points) Considers n nodes numbered 1 through n, each holding a k-bit value. Node 1 wants to find the parity of the n*k bits collectively held by the n nodes. One solution for this will be for node 1 to obtain the k-bit values from nodes 2 through n, and then compute the parity. This will require (n-1)k bits of communication. Suggest a more efficient algorithm. What is the worst-case communication complexity (in bits) using your algorithm? Nodes 2…n can send a 1 if the number of 1s in its k-bit value is odd or a bit 0 if it is even. Node 1 can then compute the overall parity. This algorithm requires (n-1) bits of communication. ! # " \$ & ! % ' & ! & ' %' & %' ' ( \$ ) * , \$ \$ \$ \$ , + * \$ - ! . , ! " . + ! + ! / . & ' ! ' & %' ,& ' %1 ' & ' 0' & ' 0' / / 0 0 " ! # 2 3 . - 4 ! 0 +# . ! 4 0 . + ' -' 0' !& & 5 ! ! ( ! 0 )) 4 / ! ! ! 12 * * '. 3 12 + * * '# 3 ! )) . ' + 44 - 6 3 , - 7 \$ 8 ! , % # , ! 9 ! ! . ) ) ) - : ) ) ) - % ) , + , 0 + \$ ) -# 1\$ ) . - ! + ; \$ 67 8 . 2 < 6 1+ 6+- * = / ) 60 \$ )3 )5 ! + 3 \$3 1+ - 1 # ) + , 9 :; ( 7 8 + \$0 +33 6 %1+ 6\$ % +3 \$ ...
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