{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

notes14 - ECE 562 Fall 2010 Equalization • If we cannot...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ECE 562 Fall 2010 Equalization • If we cannot eliminate ISI by satisfying the Nyquist condition, we are left with the following model for the received samples after filtering Z k = L- 1 X ` =0 h ` s m k- ` + W k , k = 1 , 2 ,... (1) where { h ` } represent the effective channel coefficients taking into account the combined effects of the transmit filter, channel, and receive filter. We make the following assumptions: ◦ The noise terms { W k } can be assumed to be i.i.d. CN (0 ,N ), if we assume that we sample at the receiver in such a way that the impulse response equals 1 at t = 0, and equals 0 at other multiples of T s . ◦ The transmitted signal is linearly modulated so that s m n = p E m n e jθ mn . We will further usually assume that symbols are equally likely so that E [ | s m n | 2 ] = 1 M M X m =1 E m = E s ◦ We normalize the channel so that ∑ L- 1 ` =0 | h ` | 2 = 1. Thus the average received symbol energy equals E s and the received symbol SNR equals γ s = E s /N . We assume that....
View Full Document

{[ snackBarMessage ]}

Page1 / 2

notes14 - ECE 562 Fall 2010 Equalization • If we cannot...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online