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p605hw2f08wsoln - U sci/45 Phys 605 Homework 2 Due 5pm...

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Unformatted text preview: U) sci/45' Phys 605. Homework 2 Due 5pm, Monday, September 22, 2008 Problem 2—1: [10 pts.] Consider a system of interacting particles, each with mass mi. Show that the magnitude ROM of the position vector for the center of mass is given by 2 2 2 1 2 M RCM = MZmi'ri — EZWiijfi, i is where n; is the magnitude of the position vector of the i—th particle and nj is the distance between particles 2' and 3'. Note: take n,- E 0. Problem 2-2: [10 pts.] Consider a thin vertical disk of radius a rolling without slipping on a horizontal plane (see pg. 15 in the Goldstein text and/or my class notes Section 2, pg. 2—6). Four generalized coordinates describing the configuration of the disk at any time t (as defined in the class notes and text) are (.13, y, 6, 915). The discussion in the text and class notes shows that the rolling without friction constraint is expressed by two differential constraint equations: (in: — asin qu5 = O, dy+acos€d¢ = 0. This problem is to show that this constraint is nonholonornic. If it was a holonomic constraint, then two functions would exist such that G1(w,y,6,¢) = 0 and G2(s:,y,6,¢) = 0 and the difl’erential constraint equations above would be the exact differentials: dG1 = 0 and £2 = 0. Thus1 we need to Show that it is impossible to find two such functions. (a) Show that neither of these two difl’erential constraint equations is an exact differential as written. Hint: see class notes pg 2—73.. (h) Fin‘ther, show that no integrating factor function exists (see class notes pg 2—7b) for either differential constraint equation that will turn it into an exact differential. Completing (b) we have shown neither differential constraint equation could be an exact dif— ferential. All we really needed to do was show one of the two differential constraint equations could not be an exact differential to show that a disk rolling without slipping on a plane is a nonholonomic constraint. Problem 2-3: [20 pts.] Two point masses, each of mass m, are joined by a rigid weightless rod of length 8, the center of which is constrained to remain on a circle of radius a. The circle of radius 0: lies in a vertical plane. {Only the center of the rod is constrained to the plane of the circle; the masses at the ends of the rod are thus constrained to a Sphere (of radius 12/ 2) and the center of the sphere remains on the circle] (a) Define a set of generalized coordinates for this system. (b) Express the total kinetic energy of the masses in terms of your generalized coordinates. (c) Assume the whole system is in a uniform gravitational field 9 directed downward. Write an expression for the potential energy of the system. (d) Find the Lagrange equations of motion for this system. . 3 ‘ . " Skim tiénfdé «7:17,;ch W/D ShPPEWE any? Flmnfiw ‘ls “bflhizb givg‘ifksclép ‘11-] FF “mug 7mm was}: gmwfl: EN; arm-fl 03“an 3%: @714 w.” E— 0; {K IQWM ' -’ 7 a 3‘35} 4!,- 3 :1 O 3773‘" 4" 327$ “73’ " c?” . 67¢qu __ 1:7“ >O_—§$_?_¢ [email protected] —f79—WX m7 m {9,5 I . 5: r i :W‘ax‘v 1.? E ”SE" megfikfmg—Q—g—é r5 X 32mg T034; 3 a? MA gm); 5:) ”WMGEELW; ‘ - a ‘— 2? 5—?2 =70 w IIIIIII :H‘ew 9‘5; :- 0 _ b‘o g‘ WMHQWM OW (Luz! VwW—W w 31:— wag}: 50+ 131,9 :3 $4M ———— am} \w ‘ai m: 1+ BMST Mfg MMIW ' Thug m Mir—id?» 4%:43‘4 mafia: Wk— _ (51> { NRA", Dumlo‘zfli mxravzsgxsj. u). U“: Ukbh‘éwaé}. 5m navigate, glfiie... Pro‘b, ~— VAN: GmemQée& Codi‘b ' ‘Q" 2 lyp\0.we, '\ Q‘f‘l%\u\ a; X3?— MorQ, 33%, 71g 03“ new bi: fag . 6v-iéw5‘a31’low bq-X1-‘1,? 05:43.9 $txe£k W J'PQ'UL‘ 3 9w» “fine. vuhmfi 'pre «51’ side 2 Mic; 1; MA, Ufimcwfél mmwacrfl. é‘vruhon ‘ L 0L) 9) (P > 7 (Q‘s! fines/Egg). . WM? .110, igA‘TamL KE‘ Tkmjsgj.,l9)_é_)_¢)@)_ US}, '31::ka Lag“ ‘ +9 'Xfirt-mwas +9 agave, Pcas‘yfi’ans Gaff 'HAQ. 'Jrum mafiasag ‘(fln§"xva¢ {“0 we, QWLJW'M‘Ifi a} *haécu‘fir- $312:me wads)“ (ghzbflver We? ,{QA ‘ M‘Véi mmS 'iij‘et‘tlavk‘i‘hd Was; mfimfm fiffla- was; 17d"“ra& @L‘f’K admit? a} Q”) (fife. goggpgm 4;, we, f, , OW SUK'CGLJ, 3K 5:?“ T “.1. 1:” 4T fe‘qi—NL-‘MCM —. dL“ 0 : KR) "' I o v‘ m -— , 7. W, I ~ w «fl .Bgmus—L w_wm_e4:}e.<{ baffrgmg mi thLx (:2? egg; wmsé' {VJML Vegan}? 9" MM! 17 feJantivg-l-o +74; 1%” My 9 .anw a?" Mass :5, gun-h 1&9}. 7/ ‘la¢9 :1 a} / "LI 1:; :1 “4);.“ ”£559 4 7;”: ¢ .1 , y M. 2) _.. M ((9 v 53.39:? ) .._._.,.__, A .,.. gW éi—P fl , $3?“ M Z.- .. L‘MbgkvmmflaL Fonda ...— BOIW comijwoefi, _ ; 6T $53M mfi' (ELM 4a m MM 5% 11a, WmL bwdt a? (Milo; CL) , *_ , midget _w__._wmw__ _. ovwga‘x + ices? _ , L ’ v :: —- LW%,AO.( MEAL .EflfikTLfir-QM? E1, 9‘? may: .MLHWLW _ _ ,. ,, Lgegafigfigi): “r" -\/ _ ' - _. 716‘» 2 ‘2 . 1. ‘2 - f ‘— W‘XLLQr-d + 11(19 + Smeq) )1 + Zmiészg-LQ? ' iFL _ 3L ‘ ...
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