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ReviewQ1

# ReviewQ1 - The following Ms’t‘LsB code defines two...

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Unformatted text preview: The following Ms’t‘LsB code defines two signals that are then summed: tt = -2:ﬁ.ﬂﬂl:2; x31 = 2*ees{ 5*pi*{tt — 3} l; XEE = eoei 5*pi*tt + pif4 )5 xx xxl + xs2; (a) If the Signal m1 m mne‘qpﬂnds [‘3‘ the Mil-THEE “BEE?!” K31, determine the eemples amplitude X: that can be used to represent an (t) as E‘li‘e{XH_a-u! (h) It" the signal :tr(t} corresponds to the MATLAB 1sector me. then it is possible to express LEG] in the form : Ellis? {Ac-ﬂ taj at} Detetmiue the numerical values of ail, a”), and tr. (e) Make two complex plane plots to illustrate how complex amplitudes {phasors'} were used to solve part (b). On the ﬁrst plot, show only the two complex amplitudes tphasots} that were added; on the second plot, show your solution as a vector and the addition of the two complex amplitudes as vectors (head-toutail). Use an appropriate scale es the grid below. (a) The signal a:[l] = 5 enigmat) is periodic. Determine the fundamental period {Tn} of {I3} The AM signal s(t} —- 8cos{5ﬂt — 2i oosﬁ’t 1) will have a nonzero component in its spectrum at a: L 493 radfs. Determine the complex amplitude [Aim] of this one spectral component. (c) The instantaneous frequency},I ofthe linear-FM chirp signal Mt] :2 Tr1os(.F§t”I[}et2 + rim—sf.) will change by FHz per second. Determine F { in Haa‘scc). {a} Fer the sinuseid pletted belew. determine its amplitude, phase, and frequency {in radfs}. A eesﬁat + {p} _'|'—|'_" 0-5 i i : : ' ' : i ' : i ' ‘ —e.5 ~15 —8—T—6—5—4—3—2—1 012 3 4 5 E F’ 8 Timettsee} {b} Plet the spectrum of sift) 2 3 ees (Bart — taxi-El] — 2 sin {at --|— rrf3]. Be sure to label all the frequencies and eemplex amplitudes. {e} Plut the spectrum er‘mt) _ It! — I) where sit] is given in {h}. Several signals en‘e pinned bnlnw along wiLh Lheir corresponding spears. However, they an: in a randntn order. For each of the signals (3H9). determine the correct spectrum [III—{5}. Show your reasoning for possibie partial credil. (=1) _ . _ . _ 5; _ _ : A; *1 - '7- -'~. RU) v i s} g n? ‘3 —2 —1 D 1 2 3 -1.5 -U.5 D 0.5 1.5 Timerisec} Frsqucnuy {Hz} -.'3 -2 -‘1 D 1 2 3 '2 U 2 Frequency {H2} (3) 4 Pi. ﬁg X01] 2 a}; “5; _ ; -; . D I . -3 -2 -1 D 1 2 3 -1.5 CI 1.5 —3—2-1n123 -101 'l'imef{s€:c} Frequency {Hz} (c) 5 ........ .. (5) 4 s. ,w as i-nr' *? x(i) 0 X602 . . _ I I II I I r v I I V v _. I _ _ -3 -2 1?‘i D 1 2 3 -2 -U.5 U 0.5 2 Timemssc) Frequency {l-lz} ...
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ReviewQ1 - The following Ms’t‘LsB code defines two...

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