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Unformatted text preview: u (0) = 10, and develop a series compensator D ( z ) that achieves u ( kT ) = u (3 T ) ,k ≥ 3 y ( kT ) = 1 ,k ≥ 3 (the control from part (a) achieved the above result for k ≥ 2). To do this, you’ll set Y ( z ) U ( z ) = ˆ b 1 z + b 2 z 2 + a 1 z + a 2 !ˆ z-p z-p ! . Pick p so that the sum of the numerator coeﬃcients is 1 / 10, and proceed with a deadbeat control for this plant. Explain why this should achieve the desired result, and compute D ( z ). Again plot u ( t ) and y ( t ) with a unit step reference, but now with the now D ( z ). Is the input magnitude constraint met?...
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This document was uploaded on 02/08/2012.
- Spring '09