problem03_25

University Physics with Modern Physics with Mastering Physics (11th Edition)

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3.25: Take y + to be downward. a) Use the vertical motion of the rock to find the initial height. ? , m/s 80 . 9 s, 0 . 20 s, 00 . 6 0 2 0 = - + = + = = y y a v t y y m 296 gives 0 2 2 1 0 0 = - + = - y y t a t v y y y y b) In 6.00 s the balloon travels downward a distance m 120 s) s)(6.00 0 . 20 ( 0 = = - y y . So, its height above ground when the rock hits is m 176 m 120 m 296 = - . c) The horizontal distance the rock travels in 6.00 s is 90.0 m. The vertical component of the distance between the rock and the basket is 176 m, so the rock is m 198 m) 90 ( m) 176 ( 2 2 = + from the basket when it hits the ground. d) (i) The basket has no horizontal velocity, so the rock has horizontal velocity 15.0 m/
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Unformatted text preview: s relative to the basket. Just before the rock hits the ground, its vertical component of velocity is m/s 78.8 s) 00 . 6 )( m/s (9.80 s . 20 2 = + = + = t a v v y y y , downward, relative to the ground. The basket is moving downward at 20.0 m/s, so relative to the basket the rock has downward component of velocity 58.8 m/s. e) horizontal: 15.0 m/s; vertical: 78.8 m/s...
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This document was uploaded on 02/04/2008.

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