p0108 - 12 amu 1 / 2 nm 1 / 2 pN 1 / 2 Thus, if we...

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1.8. CHAPTER 1, PROBLEM 8 9 1.8 Chapter 1, Problem 8 Since force ( F ) has units of mass ( M ) times length ( L ) divided by time ( T )squared ,we can say F = ML T 2 = T = ± ML F So, noting that there are 6 . 023 · 10 26 atomic mass units in 1 kilogram, 10 12 picoNewtons in a Newton and 10 9 nanometers in a meter, there follows, 1sec= ± (6 . 023 · 10 26 amu) (10 9 nm) 10 12 pN =0 . 78 ·
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Unformatted text preview: 12 amu 1 / 2 nm 1 / 2 pN 1 / 2 Thus, if we introduce the picosecond (psec), this equation becomes 1 psec = 0 . 78 amu 1 / 2 nm 1 / 2 pN 1 / 2 Therefore, to achieve consistent orders of magnitude for this system of units, the logical choice of units for time would be the picosecond....
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This note was uploaded on 02/09/2012 for the course AME 309 taught by Professor Phares during the Spring '06 term at USC.

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