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Unformatted text preview: 3 times the first equation. Thus, the equations are linearly dependent so that there must be 1 additional dimensionless grouping. In the present case, this means there is one such grouping. We can solve the first and third equations immediately for a 1 and a 2 , i.e., a 1 = 1 2 and a 2 = 1 2 Substituting the values of a 1 and a 2 into the dimensional equation, we have [ a ] = [ p ] 1 / 2 [ ] 1 / 2 Therefore, we expect a to vary according to a = constant p...
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This note was uploaded on 02/09/2012 for the course AME 309 taught by Professor Phares during the Spring '06 term at USC.
- Spring '06