p0352 - 302 CHAPTER 3. EFFECTS OF GRAVITY ON PRESSURE 3.52...

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302 CHAPTER 3. EFFECTS OF GRAVITY ON PRESSURE 3.52 Chapter 3, Problem 52 Figure 3.37: Hinged gate. For a circular gate, the area and moment of inertia are A = π R 2 ,I = π 4 R 4 Thus, the center of pressure is z cp = z + I zA = z cp = z + π R 4 / 4 z π R 2 Hence, we conclude that z cp = z + 1 4 R 2 z Now, when H =0 ,wehave z = R , so that z cp (0) =
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This note was uploaded on 02/09/2012 for the course AME 309 taught by Professor Phares during the Spring '06 term at USC.

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