p0556

# p0556 - A and W , respectively, we have 1 2 U 2 A = W = U =...

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5.56. CHAPTER 5, PROBLEM 56 515 5.56 Chapter 5, Problem 56 U Sheet of paper Figure 5.32: Eager student performing Bernoulli’s equation experiment. From Bernoulli’s equation, we know that p + 1 2 ρ U 2 = p a since u 0 far from the student. So, the pressure difference between top and bottom of the sheet of paper is p = p p a = 1 2 ρ U 2 The paper will be horizontal when the force due to the pressure difference just balances the weight of the sheet of paper. Thus, denoting the area and weight of the paper by
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Unformatted text preview: A and W , respectively, we have 1 2 U 2 A = W = U = 2 W A Finally, for the given values, U = > : 2(0 . 01 lb) p 144 in 2 / ft 2 Q p . 0024 slug / ft 3 Q (8 . 5 in)(11 in) = 3 . 58 ft sec Also, for this velocity, the pressure difference, p , is p = 1 2 U 2 = 1 2 p . 0024 slug / ft 3 Q (3 . 58 ft / sec) 2 = . 0154 lb ft 2 = 1 . 07 10 4 psi...
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## This note was uploaded on 02/09/2012 for the course AME 309 taught by Professor Phares during the Spring '06 term at USC.

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