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p0562 - p t − p ρ Therefore the ratio of U true to U is...

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5.62. CHAPTER 5, PROBLEM 62 521 5.62 Chapter 5, Problem 62 Figure 5.38: Pitot-static tube. The static pressure for this Pitot-static tube is measured a distance r above the point where the stagnation pressure is measured and thus has more potential energy. So, p + 1 2 ρ U 2 true + ρ gr = p t Therefore the true velocity is given by U true = ± 2 ( p t p ) ρ 2 gr Now, the velocity indicated by the Pitot-static tube is U = ± 2 ( p
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Unformatted text preview: p t − p ) ρ Therefore, the ratio of U true to U is U true U = ± 2 ( p t − p ) ρ U 2 − 2 gr U 2 = ± 1 − 2 gr U 2 For the given values, 2 gr = 2 w 9 . 807 m sec 2 W (0 . 005 m) = 0 . 09807 m 2 sec 2 Hence, for U = 1, 10 and 100 m/sec, we obtain the following. U (ft/sec) U true (ft/sec) % Error 1 0.9497 5.03 10 9.9950 0.05 100 99.9995 0.0005...
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