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Unformatted text preview: across which fluid flows is the horizontal plane between the ball and the tank walls. On this part of the controlvolume surface, the absolute velocity of the fluid and the controlvolume velocity are u = 1 10 V b k and u cv = V b k 574 CHAPTER 6. CONTROLVOLUME METHOD Also, the outer unit normal on this part of the control volume is n = k . Therefore, because the area between the tank and the sphere is the difference between the tank crosssectional area, h 2 , and the area of the spheres projection on a horizontal plane, d 2 / 4 , we have 8 s 8 S u rel n dS = 88 A } 1 10 V b k ( V b k ) ] k dA = 11 10 V b w h 2 4 d 2 W Therefore, the massconservation equation simplifies to V b h 2 + 11 10 V b w h 2 4 d 2 W = 0 = 1 10 V b h 2 = 11 40 V b d 2 Solving for d , we find d = 2 h 11 = d = 0 . 34 h...
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This note was uploaded on 02/09/2012 for the course AME 309 taught by Professor Phares during the Spring '06 term at USC.
 Spring '06
 Phares

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