p0730

# p0730 - f = . 0132 , plastic . 0232 , steel . 0313 ,...

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794 CHAPTER7 . CONSERVATIONOFENERGY 7.30 Chapter 7, Problem 30 First, we note that the Reynolds number is Re D = uD ν = (7 . 5ft / sec)(1 / 12 ft) 1 . 25 · 10 6 ft 2 / sec =5 · 10 5 Also, from the inset in the Moody diagram, the roughness height is k s = 0 , plastic 1 . 5 · 10 4 ft , steel 5 . 0 · 10 4 ft , galvanized iron = k s D = 0 , plastic 0 . 0018 , steel 0 . 0060 , galvanized iron We can use either the Moody diagram or the Colebrook formula, viz., 1 f = 2log 10 X k s /D 3 . 7 + 2 . 51 Re D f ~
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Unformatted text preview: f = . 0132 , plastic . 0232 , steel . 0313 , galvanized iron Finally, the head loss, h L , is h L = f u 2 2 g L D = ^ 56 . 25 ft 2 / sec 2 2 (32 . 174 ft / sec 2 ) ^ 280 ft 1 / 12 ft f = 2937 f Therefore, we find h L = 38 . 8 ft , plastic 68 . 1 ft , steel 91 . 9 ft , galvanized iron...
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## This note was uploaded on 02/09/2012 for the course AME 309 taught by Professor Phares during the Spring '06 term at USC.

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