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p1104 - r Thus the circulation is Γ = 8 2 π Q 2 π r e r...

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11.4. CHAPTER 11, PROBLEM 4 5 11.4 Chapter 11, Problem 4 Using a circular contour with a point source at the origin, the circulation is given by Γ = - C u · d s = 8 2 π 0 u · e θ rd θ Now, the velocity for a source is u = Q 2 π r e r
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Unformatted text preview: r Thus, the circulation is Γ = 8 2 π Q 2 π r e r · e θ rd θ But, the unit vectors e r and e θ are perpendicular so that their dot product is zero. Therefore, Γ = 0...
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