p1104 - r Thus, the circulation is = 8 2 Q 2 r e r e rd...

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11.4. CHAPTER 11, PROBLEM 4 5 11.4 Chapter 11, Problem 4 Using a circular contour with a point source at the origin, the circulation is given by Γ = - C u · d s = 8 2 π 0 u · e θ rd θ Now, the velocity for a source is u = Q 2 π r e
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Unformatted text preview: r Thus, the circulation is = 8 2 Q 2 r e r e rd But, the unit vectors e r and e are perpendicular so that their dot product is zero. Therefore, = 0...
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This note was uploaded on 02/09/2012 for the course AME 309 taught by Professor Phares during the Spring '06 term at USC.

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