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p0808

p0808 - 8 K = 343 m sec Since the missile flies at Mach 0.6...

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1128 CHAPTER 8. ONE-DIMENSIONAL COMPRESSIBLE FLOW 8.8 Chapter 8, Problem 8 Problem: According to the U. S. Standard Atmosphere, the temperature in the at- mosphere is T = T a α z ,wh e r e α = 6.50 K/km, z is altitude and T a is surface temperature. On a day when T a =20 o C, a missile flies at Mach 0.6. Determine its speed in m/sec if it is flying at z =50 manda t z =3 km. Solution: At an altitude of 50 m , the temperature is T =293 . 15 K (6 . 50 K / km)(0 . 05 km) = 292 . 8K Then, the speed of sound is a = ± γ RT = ± 1 . 4[287 J
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Unformatted text preview: . 8 K] = 343 m / sec Since the missile flies at Mach 0.6, its velocity is U = Ma = 0 . 6(343 m / sec) = 205 . 8 m / sec At an altitude of 3 km , the temperature is T = 293 . 15 K − (6 . 50 K / km)(3 km) = 273 . 65 K Then, the speed of sound is a = ± γ RT = ± 1 . 4 [287 J / (kg · K)] [273 . 65 K] = 331 . 6 m / sec Again, the missile flies at Mach 0.6, so that its velocity is U = Ma = 0 . 6(331 . 6 m / sec) = 199 . 0 m / sec...
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