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Unformatted text preview: (a) Since the ball diameter is the same for model and prototype, necessarily m D m U m = p D p U p = m = p U m U p m U m D m m = p U p D p p = m = p U m U p We are given U m = 140 ft/sec and U p = 210 ft/sec. Thus, U m U p = 140 ft / sec 210 ft / sec = 2 3 Hence, since p = 24 sec 1 , we conclude that m = 16 sec 1 and m = 2 3 p 2.84. CHAPTER 2, PROBLEM 84 283 (b) If we assume the viscosity follows a powerlaw, then the viscosity ratio is m p = X T m T p ~ . 68 = T m T p = X m p ~ 1 . 47 Hence, for the conditions of Part (a), we must have T m = w 2 3 W 1 . 47 T p = 0 . 55 T p We are given T p = 75 o F = 534.67 o R. Therefore, T m = 0 . 55(534 . 67 o R) = 294 . 1 o R 166 o F...
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This note was uploaded on 02/09/2012 for the course AME 309 taught by Professor Phares during the Spring '06 term at USC.
 Spring '06
 Phares

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