450_HW_4_solutions

450_HW_4_solutions - EE 450 Homework 4 Summer 09 Nazarian...

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EE 450 Homework 4 Summer ’09 ● Nazarian Name: _________________________________________ Lecture 8:00 Assigned: Friday July 10, 2009 Score: ________ Due: Thursday July 16, 2009, 8am 1)
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2. We have t 1 = 0 and t2 = 3 μ s a. t 3 t 1 = (2000 m) / (2 × 10 8 m/s) =10 μ s t3 = 10 μ s + t1 = 10 μ s b. t 4 t 2 = (2000 m) / (2 × 10 8 m/s) =10 μ s t4 = 10 μ s + t2 = 13 μ s c. d trans-frame (A) = t 4 t 1 = 13 0 = 13 μ s BitsA = 100 Mbps × 13 μ s = 1300 bits d. d trans-frame (C) = t3 t2 = 10 3 = 07 μ s BitsC = 100 Mbps × 07 μ s = 700 bits 3. Bit duration is 1/100Mbps =10nsec However the question wants us to measure the times in terms of number of bit durations not in seconds. a) A needs to have enough number of bits such that d trans-frame equal to or greater than 2d prop =10000bit durations, this means that A should have at least 10000 bits, because each bit takes one bit duration to be transmitted, so we need at least 10000 bits in A’s
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This note was uploaded on 02/09/2012 for the course EE 450 taught by Professor Zahid during the Spring '06 term at USC.

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450_HW_4_solutions - EE 450 Homework 4 Summer 09 Nazarian...

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