This preview shows page 1. Sign up to view the full content.
Unformatted text preview: shown. y y I1=1A
4cm What is the B field at point P? x 4cm BB .
z I2=1A
Front view 3cm P Side view • What is the direction of B at P?
y y . . . z P (A)
(A) :40 y y z P (B) z P (C) . 90o
z P (D)
(D) Physics 212 Lecture 14, Slide 21
Physics Calculation
Two parallel horizontal wires are located
in the vertical (x,y) plane as shown. Each
wire carries a current of I =1A flowing in
the directions shown. y I1=1A µ0 I
2π r x 4cm BB . 4cm What is the B field at point P? B= y I2=1A
Front view z 3cm P Side view • What is the magnitude of B at P produced by the top current I1?
(µ0 = 4π x 10−7 Tm/A)
(A) 4.0 x 10−6 T (B) 5.0 x 10−6 T
(B) (C) 6.7 x 10−6 T
(C)
y . • What is r?
– r = distance from wire axis to P µ0 I (4π ×10−7 ) × 1
B=
=
= 40 ×10−7
2π r
2π × .05
:45 4cm
z r r = 32 + 42 = 5cm 3cm Physics 212 Lecture 14, Slide 22
Physics Calculation
Two parallel horizontal wires are located
in the vertical (x,y) plane as shown. Each
wire carries a current of I =1A flowing in
the directions shown.
What is the B field at point P? y y I1=1A
4cm
x 4cm
I2=1A
Front view Btop = 4 X 106 T • What is the magnitude of B at P? (µ0 = 4π x 10−7 Tm/A)
(A) 3.2 x 10−6 T
(A) (B) 4.8 x 10−6 T
(B) (C) 6.4 x 10−6 T
(C) BB .
z 3cm P Side view (D) 8.0 x 10−6 T
(D) y .
4cm 3cm z θ
:49 B1 θ 5cm
θ
θ B2 B1x = B1 cos θ
B2 x = B2 cos θ 4
Bx = 2 B1 cos θ = 2 × 4 ×10 −6 × = 6.4 × 10 −6
5 Physics 212 Lecture 14, Slide 23
Physics...
View
Full
Document
This note was uploaded on 02/09/2012 for the course PHYSICS 212 taught by Professor Mestre during the Spring '11 term at University of Illinois at Urbana–Champaign.
 Spring '11
 MESTRE
 Physics

Click to edit the document details