problem03_26

University Physics with Modern Physics with Mastering Physics (11th Edition)

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3.26: a) horizontal motion: t x t t v x x ) 43 cos (v m 0 . 60 0 0 0 so ° = = - vertical motion (take y + to be upward): 2 2 2 1 0 2 2 1 0 0 ) m/s 80 . 9 ( ) 43.0 sin ( m 25.0 gives t t v t a t v y y y y - + ° = + = - Solving these two simultaneous equations for 0 v and t gives m/s 26 . 3 0 = v and s 51 . 2 = t . b) y v when shell reaches cliff: m/s 4 . 2 s) )(2.51
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Unformatted text preview: m/s 80 . 9 ( 43.0 sin m/s) 6 . 32 ( 2-=-° = + = t a v v y y y The shell is traveling downward when it reaches the cliff, so it lands right at the edge of the cliff....
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This document was uploaded on 02/04/2008.

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