MCB 450 SU11 Exam II_KEY - Name NetID Please print your...

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Name: __________________________________ NetID:_________________________ 1 Please print your Name and NetID at the top of ALL pages of this exam. Only non-graphing calculators are permitted for use on this exam. MCB 450 Summer 2011 Exam II KEY July 18, 2011 Graph paper is provided. R = 8.314 kJ K -1 mol -1 F = 96.5 kJ V -1 mol -1
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Name: __________________________________ NetID:_________________________ 2 [FAD] and [FADH 2 ] signifies that these species are enzyme‐bound. For enzyme‐bound FAD/FADH 2 couple consider the ξ°= 0.05 V
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Name: __________________________________ NetID:_________________________ 3 Part I: Multiple choice (2 points each; total 40 points) 1. A plasmid used in cloning, pBR322, contains a gene conferring tetracycline resistance (Tet R ) and one conferring ampicillin resistance (Amp R ). The Amp R gene is opened with a restriction endonuclease and a piece of foreign DNA is inserted. The resulting chimeric plasmid is then resealed with DNA ligase and used to transform E. coli cells. What growth characteristics will bacterial cells containing the chimeric plasmid exhibit? A. They will grow on media containing both tetracycline and ampicillin. B. They will grow on media containing ampicillin, but not tetracycline. C. They will grow on media containing tetracycline, but not ampicillin. D. They fail to grow on media lacking tetracycline and ampicillin. 2. In the RNAi technique, the protein complex that cleaves the target mRNA is: A. Dicer B. RISC C. DNA polymerase D. RNA polymerase E. None of the above 3. If V max = 100 μM sec -1 and K m = 2 mM, the velocity of the reaction when [S] = 20 mM is: A. 9.1 μM sec -1 B. 91 μM sec -1 C. 100 μM sec -1 D. 33.1 μM sec -1 E. 101.3 μM sec -1
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Name: __________________________________ NetID:_________________________ 4 4. Using Michaelis-Menten equation answer the following: At what [S] would an enzyme with a K m of 0.005 M operate at one-quarter of its maximum rate? A. 1.33 x 10 -3 M B. 16.7 x 10 -3 M C. 167 x 10 -3 M D. 1.67 x 10 -3 M E. 1 x 10 -3 M 5. When 10 μg of an enzyme with molecular weight 50,000 is added to a 1L solution containing its substrate at a concentration 150 times the K m , the enzyme catalyzes the conversion of 75 μmoles of substrate into product in 3 min. What is the turnover number of the enzyme? A. 1.25 x 10 4 min -1 B. 12.5 x 10 4 min -1 C. 37.5 x 10 4 min -1 D. 6.25 x 10 4 min -1 E. None of the above 6. Michaelis constant K m is a measure of: A. The activation energy of the reaction B. The free energy difference between the reactants and the products C. The difference in activation energy of the enzyme-catalyzed and the uncatalyzed reaction D. The rate at which product recombines with enzyme to form the enzyme-substrate complex E. The affinity of the enzyme for the substrate
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Name: __________________________________ NetID:_________________________ 5 7. The effect of which kind of reversible inhibitor of a Michaelis-Menten enzyme-catalyzed reaction can be overcome by increasing the substrate concentration? A.
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MCB 450 SU11 Exam II_KEY - Name NetID Please print your...

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