MCB450SU10_ExamIIKEY - 2 O 25. (a) 1; (b) 2; (c) 2; (d) 2...

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MCB 450 Summer 2010 Examination 2 – Answer Key 1. A 2. D 3. B 4. E 5. D 6. D 7. D 8. A 9. A 10. D 11. D 12. A 13. B 14. C 15. D 16. C 17. A 18. A 19. C 20. E 21. NAD+ must be regenerated by the reaction leading from pyruvate to X. This is necessary for the glyceraldehyde phosphate dehydrogenase reaction to continue. 22. IAA inactivates glyceraldehyde phosphate dehydrogenase by combining irreversibly with a cysteine –SH group, thus acting as a poison to the glycolytic pathway. 23. The aldehyde carbon of glucose is the C1 carbon. This would give label in the methyl group of pyruvate. 24. Glucose + 2 ADP + 2 Pi = 2 lactate + 2 H + + 2 ATP + 2 H
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Unformatted text preview: 2 O 25. (a) 1; (b) 2; (c) 2; (d) 2 26. (a) P time PNP Ac (b) The reaction is a bi-bi ping-pong mechanism. 27. (a) (b) The plot shows competitive inhibition since Vmax is unaltered. 28. (a) Plot is given below. (b) Vmax = 15.15 mmol ml-1 min-1 ; Since the K M is that substrate concentration giving half maximal velocity, we can estimate the K M accurately from the given data set as being 0.4 mM. (c) The inhibitor competes with the substrate for a common binding site on the enzyme. (d) (e) Yes (f) Slope inhib = Slope unhib (1+[I]/Ki) 0.0268 = 0.0528 x (1 + 0.2 mM/Ki) Ki = 0.2 mM...
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This note was uploaded on 02/09/2012 for the course MCB 450 taught by Professor Mintel during the Spring '07 term at University of Illinois at Urbana–Champaign.

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MCB450SU10_ExamIIKEY - 2 O 25. (a) 1; (b) 2; (c) 2; (d) 2...

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