week-1-solns

# week-1-solns - EM PEGELCr-q Pam ‘ foci’rl Problem No...

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Unformatted text preview: EM??? PEGELCr-q Pam ‘ foci’rl Problem No: 12-5 (p. l6) MECHANICAL I Name: Sc w? I aw 5‘ ENGINEERING Date: DEPARTMENT [HW Team #: Prublcm Stalcmeni from Text: A paniclc is moving along a straight line with the acceleration a =(I21— 31"} 1'th2 . when: r is in seconds. Determine the velocity and the posiliun ofthe particle as a function ot'tirnc. When t = 0: v = D and s = 1511. Given: 0‘2 1- * S’tQ) I"1/5'z A1 L'Or) V(°)=O S“ (0) 7 I 5- Fr Fmd {3 (L) System Sketch 1 FBI): 3(1) Tyne of Problem I Plan of Action: Peéirh‘Qur Mafia/w 9 h,- Iiﬂ L: O :.A7€jrcife 3(1 'fL/rLC, :1. jar V(t) c-AJ {(1’) Solution: Problem No: I2-6 {p.16} ENGINEERING MECHANICAL _ Name; 99 u. r rah, s: "— ’ DEPARTMENT HW Team #: ‘ Problem Statement from Text: A ball is released Item the bottom oran elevator which is traveling upward with a velocity ol‘ﬁ not. It‘ the hall 5trike5 the bottom ot'the elevator shall in J 5. determine the height ol‘lhe elevator from the bottom ofthe shan at the instant the ball is teleased. Also. ﬁnd the velocity ol‘the ball when it strikes the bottom ol‘the shaﬁ. Picture from Text: None Given: \./‘F c)? “ 65/:- f' ‘36”): 0 (alt-L ' 32.? fit/:1 ‘ Itnker LP'WF‘t J- fkdr" d' System Sketch / FBD: Tme of Problem ! Plan of Action: {\Decnlmcc-r Mailer. ﬂlvc Er Lfejra'c Hate! 1-9 fie: a"! a; ‘ Prublem No: [2-3' (p.l6) MECHANICAL Name: 39 L u T I 0N3 l ENGINEERING -—————__ _ _. _ _ Date: DEPARTMENT | Hw Team n: Problem Statement from Texi: A car has an initial speed ol‘25 mjs and a constan! deceleration of3 mls“. Determine: the velocin ot‘the car when t = 4 s .Whal is the displacement nl'lhc car during the 4-5 time interval? How much time is needed to strap the car? I’iqun: 110m Texl: None Given: 3(0) ‘ + 25.7, 32.0% =3 w 9(a) .- 0 Find: 3(4m) §(4 F“) v true H S”? ;> v(£m() = 0 ._.__9 ___) Tvpe of Problem I Plan of Action: we) ~' 231/; V9,“) — 7 Vectd'mear Fjof‘c“ .4) —.u d(c)7‘“? «jr‘ d .T ) ‘3, I’Mmr“ , e Lyric n 3&1! v(1) L.“ 5(1) é—— (It 4' Solution 3“) Jun) gt (-7)Jt a #3:: + c, gel-I {c'f Cy»J ' 3(9)— +25- ‘ ‘ i C; _) C}: Problem No: [2-] l (p.16) MECHANICAL Name: 50:. o r Ion—x 3 ‘ ENGINEERING _ ‘ DEPARTMENT HW Team #: Date: Problem Statement from Text: A particle travels along a slraiglu line with a velocity v = {12 — 313} nus. where r is in seconds. When I - I 5.1hc particle is located 10 m to the leli ofthc origin. Determine the acceleration when t = 4 s. lhe displacement from t = U to 1 = 10 s. and the distance the particle travels during [his time period. Given: 7 (’7 '31?) “‘/-' 36”“) 3 “ Ill-7H [inure from Text: None F' d “’(«r ) s stem SketethBD: "1 : Cf Yet 43 {Aidan 5-(9) an! 5(lr0rec) Sta-J [0.49. troy-J it" lG'ct Tme of Problem / Plan of Action: RE: I_I..-.{or M-fien “’ —). DJFUVHUH' Iri‘fﬂrrrﬁ f8 :3!" 5‘31.“ ﬁr r-Me who ﬁv’<&h7)r 0 Solution: 0—"? 3(1) =6I'2-3mc?) m Tdk! Jcr‘Vol've of +9 3t! 5M f: (aw-ﬂ (my?) ' ?rer 3“) '- 6' 61) rbi/rz 3(11‘¢)r ‘ ((f) '9 d('Trn)-‘ "-21:1/9 T“ "WWW J”F{“‘““‘i"’r FM e 13(1) (Fm... vol) Fly! K S_3(1£’"'lr) 0"" —7v(/C7H) v we "“ ? 9(6)’ fﬁdu’t ' f(12-3’(?)./t= I? t- f: ‘C. = V226 413% A?” game”? c.n_,/.¢.c,.' ;(;m).~-lo t l? we (mimic! a (1:4; _,.. 9(L)= (Ht «(F—'21) n1 Ham) = I2(c) ~ (oil’v 2r 9 21(9) r -?I a ?‘(l0:u) -‘ l'Z (lc)~(l0)J- Z’l 7) g:(/Crtc)= ‘90! «a 4-5: -‘ ;(lr)";(c): ~901-(m) Q5.- «ch’». T": WW” "UH-“r ’WI fw‘” '*"“”7 (my l7.“ sin-F: r2 , Jemima“; U31“! I‘lﬂrf/I-‘f‘. Ur t:r«-.( I"? "fqu U“¢I(rut¢r In “(1‘ ﬁqru‘.vt 1".ft‘llgﬁ- ‘3 W my 3(1,.,,)*0= 12*! mi, *9 it - 2m flu! “txwl’ Yaw): ("Z (r) *(?)’- er) :9 Him): ~52: PM - Hail [ Ever 3(1M.J]{=|[-r-<-m)1 gwlu‘: P"! +/[-90l -(- 5‘)] MECHANICAL ENGINEERING DEPARTMENT Problem Statement from Text: A particle travels along a straight-line path such that in 4 s it moves from an initial position s,\ = -8 m lo a position 55 = +3 m .Then in another 5 s it moves from 3.3 to st = -t1 n1. Determine the particle‘s average velocity and average speed during the 9-5 time interval. Given: " a". - 8M vﬁvc (LN-‘3 fit 9r“ rarf‘yvf Type of Problem / Plan of Action: {mt-r- ‘ ﬂ .( ; “-1! {p-U,Cr II‘I/rkn’ I-‘I ""t'f Name; (30". MEN’S Picture from 'l'exl: None MECHANICAL Name; S‘cttﬂ I OMS ENGINEERING DEPARTMENT HW Team #I Problem Statement from Text: A ball is thrown with an upward velocity ol'S mls from [he top ol‘a lU-m high building. One second later another ball is thrown venically from the ground with a velocity of In mﬁs . Determine the height from the ground where the two balls pass each other. Given: Gulfﬂ " 129(5)" +5179 Siné’)f “to” .3 df£)”9-3l h/r‘ Picturg 1mm Tm: None Ha" Type of Problem / Plan of Action: Recf.laﬁ‘ur Morn-n -) inrhfrlmt’ Ttuftt J" (:1!r Ir." r- , - Solution: AHA 3(1)" ' 9-?! r‘o/rT (at) farm! rt J ( 92:),n g : ‘ciow “9-8! h/rf r 3 -' i C! T) Kaylﬂlgflr Ccprﬁa.r..u' I. : 33(t)*(- 932:1 + (9.2:) MA 338).- j‘x‘ﬁglthu .~ f(—9.arid7.zdtlt- «roarihmgulcgﬁ AM; ﬁcaEXow:“difwrpmﬁwg —) “ quz'l4.90'\$ ‘3, (1L) =(— <f. 905‘ 1‘ 4 19.2!1 hmogf) H Tie LU”: w." It'd”?! (“Wk Other ’4‘“ 1"‘1 that! L’AQ" a(tmrt?)r (tn—tn) §n(tn—ﬁ.) ‘ TEE (ﬁrm?) 4.90:” if .S‘th +IO = —4905'1:' UJJI + :93: tw- I1: 905 fir hr—Qvf: {CC S‘A (Law): 94 (1.632 m) : — 4.903 (Laugh \$0.692) a to Sﬂ(i'ﬁrtv) : 4' g¢h1 Problem No: 12-18 (13.1?) MECHANICAL ENGINEERING Date: DEPARTMENT Problem Statement from Text: A car starts from rest and moves with a constant acceleration of [.5 Inlet” until it achieves a velocity 01'25 mfs. It then travels with constant velocity lot 6“ seconds. Determine the average speed and the total distance traveled. C P PM” A Cir: L féOJ'n Given: 1: o t, {q t.- a ? 5(5): O 5036): :«(ﬁJ .- . .‘O ‘ q 'éil—wi-p-rs c: x t 0 it c Find: ‘ (EEFJ.W,’.J( «C J anG S‘Tﬁiuf T e of Problem! Plan of Action: Q6 ( 7 JUNE” fie fﬂln‘r "-4 ‘9 —) Ir‘Cf;r.-Il€ C(11) t-lnce In J“ v(t) “a! :(t) J Solution: FROM A to 3‘ 34m Mr 23(1) -‘ l Em) .u = {.914 C” 3“ ‘lrr’; Emmy We) ‘0’ *"=’r'(¢)"C ' moms—t ) w Eta) ‘ f {3A1} M = L“? 3,10.) 7H2)m Find flit tie-.Q ’1 fl“ it fr“, G ("3 :) Snot“) - th/i 4 ch 9 Am than \$3.0»): 0- ~75(o)‘ “12..” Can-‘0 I 3909): 12:“ r 1.9 (a a 16,- imo m in,» "f, 14.40:“): .7)” (row): ;> i. (monk)? mayo FROM 6’ 15 C 39 (W 0 36(£)=l”a’_,(1_1{lt1 c”, 9 Ag, 6mm), I73 (H.150): 25‘ = Cm v,(¢)=25.,4 —; —9 5-,; (L) = f??? (Ll .u- - ’23}; + Cu 9 AM, 61c. : 3604.452) = 7229.37 2 2r(:4_¢;7)+ C26 9 CW: -?oﬁ.3 390:) ('25:. 4:22.?) m Flat, Th? J'splccemcrr u? (gt-141 CI wilt-rt t¢:tg*éG-’cc: 76.67am ﬂat): 5‘; (morn) = (25“(>g:.\$7_)—?0‘5.3’) r) 39 (£.)= I70‘Zm i709'0{ 1'; T1"ulr (— P 3L9. a! A't ‘ : ane' At ‘ 7.4.0“: 9 VM 273‘" .5 Sims l 9‘ (if) ‘ 51(6) '3 Problem No: 12-l9 {p.17} MECHANICAL ENGINEERING DWI DEPARTMENT Problem Statement from Text: A car is to he hoisted by elevator In the fourth ﬂoor Ufa parking garage, which is 48 ﬂ above the ground. li'lhc elevator can accelerate 310.6 [USE decelerali: at 0.3 ﬁlls: and reach a maximum speed ot'S ﬁls. determine the shortest time to make ll'lI.‘ liﬂ. startin from rs: and 'ndin wrest. g Flat AL g PM“ E R?" /; Tit-HE FF?" ' . = ? = Gwen: f}: 0 95 . 5} _ - Tame Fan» “:0 r VESB’WS “'0 cl“? +.é r‘l} Gar—'?{§/‘L ({crfo- 3 L-‘J' l6.) {cg-viru»? uric Find: {— fr: maize tin {IF' H”. Type of Problem I Plan of Action: {26(iJ-aq‘m Mgflﬂfi CU? UCCC/{fuf'ef 91"“ A "D g Lr" oé Er fir-‘9 Solution: chM A i?- 3: My; (ICCQlﬂ'v‘F-r-s 35:20) “Ah/r" 'I (am- :55qu .4 L icha 9 AW, emu}, CNN“.- vﬂ(o)=o : ,g(c)vc,avchrc (t) = . Sat “‘9 -: 1’ 5““(0 r IVA“) at : 1&3; 1 CM => QFFIY (5'; -. SEQ): O;.?(qr¢CM-‘J (M O .x Saar): .715? DUNN“? W’W’i‘l‘r r' "0* PWXIMu-‘va ail/cuﬂi/ IC/CCJ-I'] a; { r'/J" ’; “Lani-5". Find {tr-IQ he (‘6‘ng Va: ? Irv/5 —) Vn(tg,%) : .6 t : E7 [‘/j:>ighg_ [133”? Dl'ffcfn (e 1"‘q.,lz’((l in. kEnu? 1'“. '3') S“! ht) 2‘ ,3(!3'?3)?: FT get-"9:9 5‘3. 37 F‘ > ‘13"! 1J1"? Mquﬁj TL? eic infor rut;er rew(l\ef ? I‘ll; LEE"; '1' HUS" ﬂow tic-vi" 1'1: feuciﬁ V30 c." fr Raf—1 G M C ! Mm. (lat/vug-LW 3m) = m" Mr" (Zia)? fugmiu: “ﬂinch; Am Car/w -- x7; OW} o r a? t,¢...;+<,,,p—->Cm-Jztm {36(19): *.3x + Jim”, £0») T M (at) Jr —.3 ‘7: + .‘7 we” ARI? ECW‘i’i CHLHC'J 57:. (incl-J): 4g: h'isi......i‘.3’t + C ~'- §8(t)= ~_|§'tz 1.3“ in”, it + 45%,”: in“, Problem No: " l 9 go at. MECHANICAL Name: So i. U T I 0 NS ENGINEERING _ _ Date: DEPARTMENT HW T eam Ft: 1 Problem Statement from Text: Given: Find: System Sketch I FBI): Type of Problem 2’ Plan of Action: Solution: The vq’cH-‘I'Y {ll 6 l5 fLQ qu—Q Lent-h LC‘Hl‘x Vﬁrcuif? ezvot-‘cm; t‘fol'ul' : [I + .41., = --3"t. * -3 mm: => . 6t,-'-?tr~7(i.* t?) 22> 21;- ta TL? {affl-f‘ICA or E? t: t‘.(’ '5'QI'1Q Hint} Lcll‘. rein-“M quuaf."ﬂ‘K em.) = 96 (m .313: _-'§Ktz+'?(il‘t?) it J’q‘gq'mq (kWh)? '3 : —'f\$i'?+'3(ﬂ'l+ 2L!) x’l +4?_"S (£41214): .3 if: —. rtf’ +.9L,z M's? — {.35}le EMZ 32 Pﬁcetcrn P-ch' rrFt-‘K 2 Problem No: 12-74(p.46) MECHANICAL Name: SOLUTIONS ENGINEERING Problem Statement from Text: gimme from 'l‘ext: None The vclncity ofa particle is given by v = {1635+ 4t’j + (51 + 2)k} mrs. where r is in seconds. ll'lhc particle is at the Origin when 1 = 0. determine the magnitude of [he paniclt's acceleration when t = 2 s. Aiso. what is the x. y. : coordinate position ul‘ the particle at this instant? 3(1) (My 1‘ My; 1 (m . pm- (1,; A} c;:_;.._‘ (C r VJ Find: U ? m) S stem Sketch f FBD: A l I A. ‘3' .->_ g tux I" . 11:3;- 2' I V'('“ ' a J K' j j ( EC) K Type of Problem! Plan of Action: PEcl‘attIr-(‘u' Maﬁa-J 1‘ quflk‘ﬁtua C'r’j'”“”'- D. rrcrt.I:1-":/‘Irf(rr{.f'0 f.‘ r«' UCtht’-fl'"/,-cﬂfl0 J _ Solution: 3(:.)‘ a (3(1)) = {1056? + 4x3f1(9x.+s)h. , 04‘, : (thhr)f* O'<;7)j+@"94(13)"' Problem No: 12-79 (p.46) MECHANICAL Wine: 60L u 7 “I0 ~57 l ENGINEERING Date: DEPARTMENT I HW Team #: , Problem Statement from Text: A particle travels along the path y“ = 4 x with :1 constant speed of" v = 4 mfs . Determine their and}! components ol'thc particle's velocity and acceleration Wth the particle is at): = 4 m. Pictur; from Text: None . _ f 7. I; Give“: Jari;‘|'( firm-1"!“ 0" 1' \f X V : 4 P-x/f (Ln ._‘_"...--FI Fmd. (j “I a ‘M i' k x If S'stemSketcthBD: .’ v= 4 ‘-.'—4__4. _ Tme of Problem 1’ Plan of Action: («Eclxhnmir r‘lor-.—--‘Cd,p(:“.4 Fun-v ..__ . F’ In FIN-l X are! \f c.chciic-q uc'cul’tcrnri'rn'j’ fvf’t t1! jcqo “(I f/fhgo’r"? "'7." ((43.9 CAw-a ((1 I?) ﬁ(2y:i~£)= 3%(4rf—:)s> 45% i” wigkﬂ‘fﬁ’i) t LHJ W _. , W V "J L Y I (- g Q: A? x: 4,.” y: 4... (VJ VJ}: (Ir/n -J'_r.~,t). Timu;_u"xpc?..n-'-- {Irv-r. (I???)2 + 4c, - '2 a, =:> o": —.'3' +.§ a, (Ecru l) gtncﬁ. ti'i‘ FUl’f‘Cff Tran-JP"! m" U (oval-‘0 “ft?! fix-'1 Mtﬁﬁf Pk", “If eccentruruw .-“ {LP 4"QCI‘1CA rr Ht‘ «Ciro: I tr E'ero. N U _ f _ L??? . n , \3 T 9 1‘“ a: 9 ' W a z 2 ":a 7 1“ / it); I‘ ' ,15 6' —-—-—-;‘ 1:2 " chr: (Ernst, rm 2-4-3750 :) qx=‘.§oy (EON?) 95L" ? C(IL-IF'C'HJ ? unknown; f5 jt’ or .?2 Ina/é? 0-}: —044 {L/(l MECHANICAL ENGINEERING DEPARTMENT Name: S‘th r“ Ice}? Problem Statement from Text: A car travels east 2 km for 5 minutes. then north 3 km for 8 minutes. and then west 4 km for [0 minutes. Detennine the total distance traveled and the magnitude nfdisplacemcnt ofthe car. Also. what is the magnitude eflhe average velocin and the average Speed“? ir- Given: Cw I: ., ; ,_ Ht»! ‘3 p ) L1”. 4 i, (if. ) Find: "hr [h' f i a Ir‘..<"li") A F ['I' “In-"'f’ r 4’ 'f".!"r H 1 I I a I re Jr}, I) {purl—:- I _fu_[ v f‘ﬂv‘a ' r I-I -' . TV e ofi’roblem i Plan of Action; ﬁtt\$J'—bll I " a \$712.“. W Norif System Sketch I FBD: 4 F“ no-Ia r a _____.__. ...
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## This note was uploaded on 02/09/2012 for the course MECHANICAL EM232 taught by Professor Zollars during the Spring '11 term at Naval Academy.

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week-1-solns - EM PEGELCr-q Pam ‘ foci’rl Problem No...

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