6.44 A tubular steel shaft is being designed to transmit 225 kW at 1,700 rpm. The maximumshear stress in the shaft must not exceed 30 MPa. If the outside diameter of the shaft is D= 75mm, determine the minimum wall thickness for the shaft. Solution The torque in the tubular steel shaft is: ()1,000 N-m/s225 kW1 kW1,263.877 N-m1,700 rev2 rad1 minmin1 rev60 sPTπω⎛⎞⎜⎟⎝⎠===⎛⎞⎛⎞⎜⎟⎜⎟⎝⎠⎝⎠The maximum shear stress in the shaft will be determined from the elastic torsion formula: TcJτ=where4432JDd⎡⎤=−⎣⎦Rearrange this equation, grouping the diameter terms on the left-hand side of the equation:
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