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Exam1_sol_F10

# Exam1_sol_F10 - MAE 2300 Exam One Fall 2010 120 minute time...

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Unformatted text preview: MAE 2300 Exam One, Fall 2010 . 120 minute time limit N_ame: X? M 074/ Instructions: 1. Please write your name on each sheet in the space provided. 2. This test is closed book, closed notes, with one equation sheet provided to you (on the back of this cover sheet]. 3. For each problem, show all your work and indicate your final answer by writing it (with proper units) in the space provided. 4. Solutions with no free body diagram (to problems which require one) will receive substantially reduced credit. 5. Write out and sign the honor pledge in the space below. 6.Nea7tvtw Md“ weak. gun/L L544. - ‘1‘- - 5L Woo» rJ eubmﬂecl Um («ML Dec/ewe 0d: (most (”7 (141‘ ) coconut fun w Wle- mm M éMé AAMW MAE 2300 Equation SheetiExam One, Fall 2010 A-B:ABCOSH i-i=j-j=k-k:1 i-j:i-k=j-k=0 A x B 2 (AB sin mug” where ua is perpendiwlar to the plane containing A and B i><i=j><j:kxk=0 ixj=k jxk:i i><k=wj sine: Sinﬁ _ sin A B C «32': a2+b2—2abcosqr M=r><F FR=ZF FR=Iw(\$)dm MgifFR MR=f\$w(\$)d\$ ZF=0 xix/1:0 Name: 1. [+20 pts) Determine the angle 0 between the force F and the line AB. W5 death“ a»? Pnowd 2 wage» [1) F.rA3-:. EYAg+H C Car-Peg‘am wedvv] (m P‘F;Q= Fh’namg :3 cJWCJ—vuw Wait ”W W0, do = (cc) F€V§+l Aggy“: E J5 FM E -— 6000mm ~o.(.3> N. r543: ‘334'41vw Mﬂtgm Ned) (I1) ‘= (is) boo (0:82» ~O.6j) - (~ 33 +41] 2‘ 600(5)a<19 600 (0-6300 3 36000696 cow: 0.3g 9": \$3.? WW (solution to Prob. 1, can’t] Name: 2. (+20 pts] A force F = 1001b holds a crate (weight 400 1b] in equilibrium. If the two cables AB and AC each have a tension of 450 lb, determine they and z coordinates for point A. A Fpmacz‘" : equul/C bvz'um» \- FED @ A 2.. ﬁeqwib Mm!“ 3.2mm: l- FED @ A. ,_ VG= — 400 E n, PM“) E“ loo 1 ._ ﬂ ‘ 1:. ac. \\° ‘_ J K 4”” \ PM -.-. ’r‘So u.“ u, I, E ﬁ 2 45 5 SamuLDi'DCC mun/ft, __ \) y be 0 (lily; \LI y-Qxfs W ”Jul “1%: ‘57, 'JJ'+(4*a):i-L 4t \‘asl 2 MW“ WW5 iE—E 9 96 450 -_—* ~ +50 ":— 3 6 lad )rnrﬂ Name: 3. (+20 pts] Replace the force system shown by an equivalent force and couple moment at point 0. 500 N 200 N 200 N ”Em/w new FR:— 300?, + 4M3} 'EOJ : 3002—3933— N W 7_,WW Wumleauq +5 HR = *(QSoXmsX ~ 2.00 C O - Soo(%)(x‘) + Boo (is) (2.6) Hz: 4.5?"5 N'w) W [solution to Prob. 3, con’t) Name: 4. [+25 pts) Spring BC is unstretched when 8 = 0° and the crank achieves its equilibrium position when 8 = 15°. Spring BC remains horizontal at all times due to the roller at C. Determine theforce F applied perpendicular to linkAD, and calculate the pin forces atA. A'vaoadﬂ ——........_-.—-——-_'—-' t. F319 «:1. 5mm 2 . ﬂown/pine, SW3 "FU'VCJL (9: 0‘ 6:45)) / 5‘: 0-3605 30—0355-345 S: 0.04?) M :7 F53 ZOBD% {0.04% an) E2: 019.35 N W.— (solution to Prob. 4, con’t] 3.WUWW WW§ ﬁ—O’M‘j Mud 1+” MM‘LF! # 4,) am: -F~(o.+\+ FAG-322m: +53 :0 —_—.>::—— W); we M 0-4” W‘— TZFX= - FMES‘F34'A'X "’ 0" Ax: +§o.é,¢v;[s +9535 ﬁx '-‘ 10%.45 N 41k :Fy3 ~me§+AJso A), =. 45.%5N M 5. [+ 15 pts) In the space provided, draw the complete free body diagram for each problem. DO NOT actually solve the problem. DO NOT write the equilibrium equations. Make sure your free body diagram includes all the required elements. [a] (+8 pts) Draw the FBD of link AB. Draw part (a) FBD here. 450 “9 goo llo Draw part (b) FBD here. ) '1" x H We \$06.20., a l w D ., Ii: IQ wan ; A é... ...
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Exam1_sol_F10 - MAE 2300 Exam One Fall 2010 120 minute time...

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