EE_4002Project1

EE_4002Project1 - EE 4002: Project #1 Due day: 10.20.2004...

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EE 4002: Project #1 Due day: 10.20.2004 An elevator, shown schematically below is driven by the DC motor by using the mechanical gear. The mass of the fully loaded cabin is equal M Cab = 7X, where X is the last two digits of your ID number (if the first is zero (e.g. 06), use 8 (i.e. 86)). The mass of the counterweight is M Ctw = 0.25 M Cab . The cabin should move up at speed 1 m/s when is fully loaded. The data of the mechanical elements are as follows: The gear ratio: 10 L G M r K r = = , The gear and pulley moment of inertia is (J p + J G ) = 0.1 X kg m 2 , The combined friction coefficient of the gear and pulley is B = 0.1 X N m/ (rad/sec), The radius of pulley R = 0.2 m. 1. Calculate the power of the motor and select (using Web Site of producer or vendor on internet, e.g. e-motorsonline.com ) the appropriate separately excited DC motor for driving the elevator. To determine the ratings of the motor use the following criteria and data: Available voltage supply V
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EE_4002Project1 - EE 4002: Project #1 Due day: 10.20.2004...

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