EE 4002: Project #1
Due day: 10.20.2004
An elevator, shown schematically below is driven by the DC motor by using the
mechanical gear. The mass of the fully loaded cabin is equal M
Cab
= 7X, where X is the
last two digits of your ID number (if the first is zero (e.g. 06), use 8 (i.e. 86)). The mass
of the counterweight is M
Ctw
= 0.25 M
Cab
. The cabin should move up at speed 1 m/s when
is fully loaded. The data of the
mechanical elements
are as follows:
•
The gear ratio:
10
L
G
M
r
K
r
=
=
,
•
The gear and pulley moment of inertia is (J
p
+ J
G
) = 0.1
⋅
X kg
⋅
m
2
,
•
The combined friction coefficient of the gear and pulley is B = 0.1
⋅
X N
⋅
m/
(rad/sec),
•
The radius of pulley R = 0.2 m.
1.
Calculate the power of the motor and select (using Web Site of producer or vendor on
internet, e.g.
emotorsonline.com
) the appropriate separately excited DC motor for
driving the elevator. To determine the ratings of the motor use the following criteria
and data:
•
Available voltage supply V
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 Fall '06
 Scalzo
 excited dc motor, motor armature resistance, fully loaded cabin, Available voltage supply, voltage source Va

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