Unformatted text preview: To compute the work we calculate the component of the force acting in the direction of the particle's displacement. In this case, this quantity is simply F sin θ . Again, this force acts over an arc length given by rμ . Thus the work is given by: W = ( F sin θ )( rμ ) = ( Fr sin θ ) μ Recall that τ = Fr sin θ Thus W = τμ Surprisingly enough, this equation is exactly the same as our special case when the force acted perpendicular to the radius! In any case, the work done by a given force is equal to the torque it exerts multiplied by the angular displacement. For you calculus types, there is also an equation for work done by variable torques. Instead of deriving it, we can just state it, as it is quite similar to the equation in the linear case: W = τdμ Thus we have quickly gone through deriving our expression for work. The next thing after work we studied in linear motion was kinetic energy, and it is to this topic that we turn....
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This note was uploaded on 02/09/2012 for the course PHY PHY2053 taught by Professor Davidjudd during the Fall '10 term at Broward College.
 Fall '10
 DavidJudd
 Physics, Force, Work

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