14_CEG 4012 Notes Fall 2011 CEG 4012 Notes Fall 2011

14_CEG 4012 Notes Fall 2011 CEG 4012 Notes Fall 2011 - g...

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S 15 a Example 3: Find the stress increase at Point T al a depth of 6 1t. 2' 4' T q = 1000 psf : 3' Solution: for <D m = Biz = ':J. .)(" 6··>·~ n = Uz = ~), : c·s 0 in chart find I = 0.0(, I for Q) m = BIz = 3/~ v.n) n = Uz = 'I!" t.F) in chart find I = 0,10<.> acrv = (D.6~1' 0.1(0) (JlIoo(~r)" //,/ ~r+ o General case under a rectangular footing: ~ I\cr,= q (I, + 1 2 + 1 3 + I,) ~ ~15' U 1.5' 3' 1 3' q = 1000 pst Plan 3' 3' Find the stress increase at Point U under the foofing center at a depth of 6 It. 4 x influence of one auarter section m = Biz = 1.5/6 = 0.2 C n = Uz = 3.0/6 = 0.,0 in chart find I = 0.0 1 1
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Unformatted text preview: g dav = &lt;., (o.oifr) (,DO{}{'Jrr /1:Lpfl Solution: a Example 4: o Variable loading: The load in each seclor may vary and :. !1CJ&quot; = L (ql II) (for the general case above tl.cr v = q, I, + q2 1 2 + q3 b + q4 1 4 ) A __--B~ C HI lr=t D F E .6.0 v = q (IACDH -I BCD1 + IHDEG - hOEF) o .6.o v located outside of loaded area: o Example from an old exam: Find the stress increase at Point V v Wall Footing q=1tst 50' 75' I 50' 1...
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