16_CEG 4012 Notes Fall 2011 CEG 4012 Notes Fall 2011

# 16_CEG 4012 Notes Fall 2011 CEG 4012 Notes Fall 2011 - /l...

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S16 Embankment Load: a Another important "shape" is the embankment (e.g. highways, dams, etc.) If the embankment material is soil then the surface load (pressure) at full height is ~ q = '1 H. Chart on next page provides influence factors due to 1/2 of embankment ~ I1Gy = q x I where I is a function of (alz) and (biz). ~ I1Gy = 2q x I for the full (symmetrical) embankment ~ Use superposition for points other than C.L.) ((t,~, Example: Find !:1C1 v at point A, 45' under the embankment centerline, and point B, 45' under the toe. !:1CJ y under centerline: Split the embankment down the middle and find influence of each side (which will be the same since the 2 sides are symmetrical). 40' 30' ., ... II b a .' :;:~,}(:\ ):::}~,:::: i 45' 'A q = lO'~ POfcf: l-'1 0 0f!..( a = l/o'~ ('-./l)
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Unformatted text preview: ('-./l) ': fO'/.,s'-: o. Y1 b = ?o'''':> (b/"t'): ~o'l'lr-: 0Â·(, I from chart c:> I = o.lfl'> !la v = 2 x q x I = Z(l.'foo ,sf) (0 . .".Â» ':-1-'2 ~ elÂ£. !:1CJ y under toe: Use superposition. Calculate influence factor as though point B is under full height of embankment and then subtract influence of added part ( ..... ,1 <>/\ '1 (0( 'it Il( 1-40' 60' 40' 40' 100' f.<o\Â£. . "t."", 40'-.. ,0 ... " .. = II. . II .. .. 45' B 8 For Q):a = 40' c:> (a/z) = 40' 145' = 0.89 b = 100' c:> (bIz) = 100' I 45' = 2.22 c:> from chart c:> I = 0.481 For Â®:a = 40' c:> (a/z) = 40' I 45' = 0.89 b = 0' c:> (bIZ) = 0' I 45' = c:> from chart c:> I = 0.23?...
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