42_CEG 4012 Notes Fall 2011 CEG 4012 Notes Fall 2011

42_CEG 4012 Notes Fall 2011 CEG 4012 Notes Fall 2011 -...

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OC Settlement Example 2: 7ft 5ft 15 ft 12 ft Find Pc under tank center: Circular Tank, 30 ft Diameter, 20 ft High, Filled with Oil, SG = 0.91, q = 20 (62.4 x 0.91) = 1136 psf p25 Use 3 sub-layers in upper clay, 2 sub-layers in lower clay. Use Boussinesq formula (or chart) tor !J.crv under the center of a circular loaded area (r = 8/2 = 30/2 = 15 ft). c}o ',. 0 At bottom ot sand: crv = 7(100) + 5(105) = 1225 pst, u = 5(62.4) = 312 psf (l(O ,~j,C/- {~ 1; '( (z = 12 ft) cr'v = 1225 - 312 = 913 pst, note tha}f c SAND~_g7 (t. - '%-~ /(' f'\ ~- cr'vt cr'Vi+!J.crvt Sub-layer 6.Zj Zicl crvt Uj (=cr'o;) zlr qi !J.crVi (=cr'OI+!J.crvt) i tt ft pst pst pst (xlr=O) psf psf pst 1 5.0 14.5 1525 468 1057 0.97 0.66 1136 755 1812 2 5.0 19.5 2125 780 1345 1.30 0.50 1136 570 1915 3 5.0 24.5 2725 1092 1633 1.63 10.38 1136 431 2064 . I 4 6.0 30.0 3385 1435 1950 2.00 \0.2~ 1136 323 2273 5 6.0 36.0 4105 1810 221) 2.40 \:O.2j 1136 243 2S"J+ P =( C.H }o (O',+.
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Unformatted text preview: ...Oy )or =( C.H}o (0'0 )+I>-toH }o (O.,+. ...Oy ) c 1 + ega' 1 + e 9 cr l 1 + e 9 cr l o C f-', ~ Sub-layer H (J'V\ cr'vt+!J.(Jvt (C~HI} (0'.) !J.Hi eOi CRi CCi (=cr'OI) (=cr'Oi+!J.crVl) cr'Ci 1 + e OI 09 a'lj i ft ft pst pst pst CR Cc 1 5.0 1.40 0.04 1057 1812 2050 0.019 0.019 0.40 2 5.0 1.40 0.04 1345 1915 2050 0.013 0.013 0.40 3 5.0 1.40 0.04 1633 2064 10 So 0.008 j),oll 0.40 0.003 4 6.0 1.00 0.05 1950 2273 '2.'100 0.008 0.50 O,ooCl 5 6.0 1.0 0.05 "). .,. .,> 15'~:) "Z. '100 0.002 0.50 0.030 O.o~.2. . Total Consolidation Settlement = I:.!J.Hj (~I, t\ in) O,oY3-,-.-/...
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This note was uploaded on 02/10/2012 for the course CEG 4012 taught by Professor Staff during the Fall '08 term at University of Florida.

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