47_CEG 4012 Notes Fall 2011 CEG 4012 Notes Fall 2011

47_CEG 4012 Notes Fall 2011 CEG 4012 Notes Fall 2011 -...

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p31 o Using the relationship between T and U we can answer the initial questions about %Pc: 1. What %Pc will have occurred at a given time? 0% Le. know t, cV, H, N ==> what is U? (.. -_ c.., t S"lv<' -lit J-- - L H /rJ) 1 u 100% + __ L __ -=:=::==L. T 2. How much time is required for given %Pc? 0% U = % Consolidation T = Time Factor Le. know U, cV, H, N ==> what is t? t;fS ~ ~'I\J T For Sf~[ Ilie ~ lJ) .fk", $o\vt t~r t: T ( "IN) 1. - (v u 100% L __ L_-=:::==-+ T OU D Time Factor T Average Case 1 Case 4 Consolidation (1a,1b) Case 2 Case 3 U% 0 0 0 0 0 5 0.0020 0.0030 0.0208 0.0250 10 0.0078 0.0111 0.0427 0.0500 15 0.0177 0.0238 0.0659 0.0753 20 0.0314 0.0405 0.0904 0.101 25 0.0491 0.0608 0.117 0.128 30 0.0707 0.0847 0.145 0.157 35 0.0962 0.112 0.175 0.187 40 0.126 0.143 0.207 0.220 45 0.159 0.177 0.242 0.255 50 0.197 0.215 0.281 0.294 55 0.239 0.257 0.324 0.336 60 0.286 0.305 0.371 0.384 65 0.342 0.359
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Unformatted text preview: 0.425 0.438 70 0.403 0.422 0.488 0.501 75 0.477 0.495 0.562 0.575 80 0.567 0.586 0.652 0.665 85 0.684 0.702 0.769 0.782 90 0.848 0.867 0.933 0.946 95 1.129 1.148 1.214 1.227 100 00 00 00 00 Case 4 Triangular D&gt; Case 3 Sine Curve 8 Case 1a = Case 1b Constant Linear o The relationship between T and U for 1-D consolidation depends on the initial profile of the excess pore water pressure, u, vs. depth (caused by the applied load Acrv). All cases are double drainage (N=2, top and bottom porous). Cases 1a, 3 and 4 are symmetrical about centerline and work for N=1 as well (initial distribution is 1/2 of that shown). Case 2 Half Sine Curve...
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