95_CEG 4012 Notes Fall 2011 CEG 4012 Notes Fall 2011

# 95_CEG 4012 Notes Fall 2011 CEG 4012 Notes Fall 2011 - 45 2...

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Foundation: BC10 Meyerhof Bearing Capacity Example 1: B = 30 ft , L = 100 ft, F.S. = 3.0 0,=0, y=100pet,c=200psf,\$=36',depthtoGWT=40ft 1. Of = 0, surcharge term = 0 2. GWT depth> B, use y = 100 pet with Ny term 3. Get N values w, \$ = 36': 4. Determine shape factors: ( 30ft) 2( 360) Ac, = 1+ 0.2 tan 45 + - = 100ft 2 I. ?> ( 30ft) 2( 360) Aq, =A", = 1+ 0.1 tan 45 + - = 100ft 2 5. Determine depth factors: DriB = (0 ft I 30 ft) = 0 ( 360) Acd = 1 +0.2(0)tan
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Unformatted text preview: 45 +2 = I. D 0 ( 360) Aq.,=A. .,o =1+0.1(0)tan 45+ 2 = 1.00 I,ll. 6. Determine inclination factors: ex = O' c. Ac; = )"'; = A,; = 1.00 7. Calculate bearing: I q,= cN,Ac,AcdAc; + gNgAq,AqdAqI + Y2 yBN,A",A. .,oW q, = (200 psf)(50.59)(1.23)(1)(1) + 0 + Y2 (1 00 pet)(30 ft)(44.43)(1.12)(1)(1) •--11:<' ; 61O I{ ['13,5 'N "',,"iJ f.r....
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• Fall '08
• Staff
• Harshad number, Bearing Capacity Example, Determine depth factors, Determine shape factors, Determine inclination factors

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