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96_CEG 4012 Notes Fall 2011 CEG 4012 Notes Fall 2011

# 96_CEG 4012 Notes Fall 2011 CEG 4012 Notes Fall 2011 - =...

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BC11 Meyerhof BC Example 2: sameoa",example 1 except~ ° nflusnce o4um 1. Get N values w, ~ = 28°: N c = 25.80, N q = 14.72, N y = 11.19 2. Determine shape factors: (deplh and inclination faclors are same) ( 30ft) ( 280) Aes = 1 + 0.2 tan' 45 +- = I, ". 100ft 2 ( 30ft) .( 280) Aes =1. .,s =1+0.1 100ft tan 45+ 2 = I. oS 3. Calculate bearing: I g,= CNcAes)"",A,; + gNgA", .... A,; + Y2 yBNjv"A",)J q" = (200 psf)(25.80)(1.17)(1)(1) + 0 + y, (100 pcf)(30 ft)(11.19)(1.08)(1 )(1) Q" =q"xarea =( '). 't,lL< ,,,)(30 ft)(100 ft)(1 tl2000 Ib) = ", O,! '.,,5 Meyerhof BC Example 3: arne as example 1, bur-~
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Unformatted text preview: = 37° (EbGbang Ulnl ") 1. Get N values w, ~ = 37~ N c = 55.63, N q = 42,92, N y = 53.27 2. Determine shape factors: (depth and inclination faclors are same) ( 30ft) ( 370) ,-<,=1+0,2 100ft tan' 45+ 2 = 1.2" ( 30ft) ( 370) Aq, =1. .,s = 1 +0.1 tan' 45 + -= I. ,'). . 100ft 2 q" = (200 psf)(55.63)(1.24)(1)(1) + 0 + y, (100 pcf)(30 ft)(53.27)(1.12)(1)(1) Q" = q" x area =( 103, :>-q~ fsr )(30 ft)(100 ft)(1 t 12000 Ib) = I >'1,~"1 /0-;...
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