164_CEG 4012 Notes Fall 2011 CEG 4012 Notes Fall 2011

164_CEG 4012 Notes Fall 2011 CEG 4012 Notes Fall 2011 - = 0...

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DF45 Drilled Shaft Example, Clay No static test Uniform Site Good site investigation therefore FS == 2.5 GWT at 100 tt 12 ft 25 tt 1.5 ft 5 ft ~ Stiff Silty Clay I 'Y = 105 pef I C u = 1.6 ksf Stiff Clay, 'Y = 108 pcf, C u = 1.4 ksf Very Stiff Clay, 'Y = 109 pcf, C u = 4.0 ksf = or l '(.0 IU t) ~ ~ ,. 0 ks( = 1t Bb2/4 = 1t 5 2 /4 = 19.6 ft2 =~f:,.okSf (ICIJ.(, pile weight: W ~ bearing: ql AI at = 150 pcf [(58.5 tt) 1t (2)2/4 + (7fl12)(1.5 tt)(2 2 + 52 + 2x5)] /1000 = 29.9 kips ;\ _ vJ o - ~ ~ Cy ') rIA -Ul~ side shear: use a method, note a
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Unformatted text preview: = 0 for 5' from head and (1.5 ft + B) = 3.5 ft above toe Layer Depth Thickness Cu fs = aCu As=1tB~L as = fsA s ft ft ksf a ksf ft2 kips 1 0-5 5-6 2 5-12 7 1.6 0,5" S' D.~8 ~t.{ ,'t 3 12-37 25 1.4 D.sS' O,':l-"1-,51-J 1. I 4 37-56.5 19.5 4.0 O,lJ<i \ I Cj'l I~'l. . ';). J L/ 5 56.5-60 3.5-c) C. 1.StB-=-l,r;~2.:':S. ",3.5 EO s ~e,'I allowable load: 105". ~.. 3'fl.f-.;L ~, 1 ~,5'...
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