176_CEG 4012 Notes Fall 2011 CEG 4012 Notes Fall 2011

176_CEG 4012 Notes Fall 2011 CEG 4012 Notes Fall 2011 - 600...

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Load Distribution Example 2: DF49 3' 3' 3' Q = 600 k M x = 100 k-ft My = 200 k-ft p = Q + Myx + MxY I -"'2-"'2 n LJX LJY L(X 2 ) J ~ 'l ~S), + H{ ,.S)1 = '10 f1 t L (y 2) = )' (').) ( ').) : ~:l (:{ 1 P max = P 1 =
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Unformatted text preview: 600 + 200(4.5) + 100(2} = 15" ~ 10 + 6. 'J.S""-= 11 k.:fJ 8 90 32 P 3 = 600 + 200(1.5} 100(2} = "1-?. k:P5 8 90 + 32...
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This note was uploaded on 02/10/2012 for the course CEG 4012 taught by Professor Staff during the Fall '08 term at University of Florida.

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