188_CEG 4012 Notes Fall 2011 CEG 4012 Notes Fall 2011

188_CEG 4012 Notes Fall 2011 CEG 4012 Notes Fall 2011 - \...

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x x SL14 o for i < 53 0 and II> = 0: the critical circle may be a toe (n=O), slope, or base circle, depending on the location of the firm stratum (DH). When II> = 0, base circles are unique in that the center of the circle will be located directly above the midpoint of the slope. These base circles are known as "midpoint" circles. Use the figure for below for i < 53°: nH I I , I , I H ,,' ,: DH , , , ,,/Midpoint 90-S/2 .~_-',' Circle ." sr-I---;::==:r=::=;---r--,---,--, o 10 1.~-~_. .::::t;::::==::::t:=-_L_-l __ .J ~ so ~ 30 W I (des) location of midpoint elrellS (after Terzaghl and Pecic. , 967) to find R for a Taylor 4 n-3 for i < 53 0 midpoint circle: 4 ( S) nH+X tan 90- 2 = (D-1)H solve for S and then R nH+X D 3 R= sinS ~ 0 2 Taylor 5 for 1< 53° o~~_ \ ..... .;::---- "l_ -- , Q'~ -- --- \ ---. . .
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Unformatted text preview: \ ..:':.:': &quot;;&quot;'./ : ,&quot;. :: .. :.': &quot;.. .. , \ \ \ :::f:.::::. .:.&quot;:-:;.-. ..&quot;.::'. . ~:: . . . . . .. use the sin rule to find R: R H/sini sin(a 2 +i) - sin(180 a 1 a 2-i) R= Hsin(a 2 +1) sinisin(a 1 +~ +i) note: if the critical circle is a toe circle (shown as such in Taylor 1 and 2 charts) then can use table below to find the center of the circle and the radius: n' i a, a2 1.0 45.00 28 37 1.5 33.68 26 35 2.0 26.57 25 35 3.0 18.43 25 35 5.0 11.32 25 37 Locatlon of the canter of critical toe eireles for I &lt; 63...
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