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Unformatted text preview: H = V OH V IH = 0.85V, NM L = V IL V OL = 1.85V Double the width of the transition region: V IL = 2.2V, V IH = 2.8V NM H = 0.7V, NM L = 1.7V 6. Transconductance amplifier & & + & & + = L OUT OUT S IN IN MS M R R R R R R G G & large R IN , large R OUT needed to maximize G M Transresistance amplifier & & + & & + = L OUT L S IN S MO M R R R R R R R R & small R IN , small R OUT needed to maximize R M 7. R OUT = v x /i x 3 equations: & x in v v = ( ) ( ) IN S Rout x in R R i i v = OUT in VO x Rout R v A v i= Solve : ( ) OUT VO x Rout R A v i= 1 from 1 and 3 Into 2 : OUT VO OUT IN S x x R A R R R i v+ = 1 1 1 Since R IN is large, R S R IN ~ R S R OUT is small & the term A VO /R OUT dominates in the denominator R OUT = v x /i x R OUT /A VO...
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This document was uploaded on 02/09/2012.
 Fall '09

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