Unformatted text preview: conductor, the contribution to the contour integral from that portion in the conductor is zero, whether the conductor is moving or not. This is because E' is the quantity measured by an observer moving with the contour (conductor). 1.1.2b Electric Field Systems The integral forms of (1.1.11) to (1.1.15) are SE. dl = 0, (1.1.24) sD .nda = pf dV, (1.1.25) Jf nda = p dV, (1.1.26) H' -di = J1-n da + D f n da. (1.1.27) These equations are valid for moving and deforming contours C, surfaces S, and volumes V (see Fig. 1.1.1). Equations 1.1.24 and 1.1.25 are the same as those used to find E and D in an electrostatics problem. The current density and magnetic field intensity have been written in (1.1.26) and (1.1.27) as J; and H' to indicate that they are the values that would be measured by an observer moving with the contour or surface at the point in question. It is shown in Section B.4.2 that 1.1.2 A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
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- Fall '11
- Magnetic Field, electric field intensity, Electric Field Systems