{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Electromechanical Dynamics (Part 1).0053

# Electromechanical Dynamics (Part 1).0053 - the upper plate...

This preview shows page 1. Sign up to view the full content.

Lmped Electromechanical Elements Volume for relating fields in S"vacuum and in dielectric-" Dielectric of _" Conducting plates permittivity e of area A Fig. 2.1.7 A parallel-plate capacitor. Example 2.1.4. Consider the simple parallel-plate capacitor of Fig. 2.1.7. It consists of two rectangular, parallel highly conducting plates of area A. Between the plates is a rectangular slab of dielectric material with constant permittivity e, D = EE. The lower plate and the dielectric are fixed and the upper plate can move and has the instantaneous position x with respect to the top of the dielectric. The transverse dimensions are large compared with the plate separation. Thus fringing fields can be neglected. The terminal voltage is constrained by the source v which is specified as a function of time. We wish to calculate the instantaneous charge on the upper plate and
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: the upper plate. To solve this problem we need the given relation between D and E, (1.1.24) and (1.1.25), and the definition of the voltage of point a with respect to point b v = -jE dl With the neglect of fringing fields, the field quantities D and E will have only vertical components. We take them both as being positive upward. In the vacuum space D, = EOE, and in the dielectric Da = EEd. We assume that the dielectric has no free charge; consequently, we use (1.1.25) with a rectangular box enclosing the dielectric-vacuum interface as illustrated in Fig. 2.1.7 to obtain .oE, = eE . We now use the expression for the voltage to write v= = Ed' -'f+dE, da'. Integration of these expressions yields the vacuum electric field intensity V E , + (Eo/e)d A-PDF Split DEMO : Purchase from www.A-PDF.com to remove the watermark...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern